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From: Sabyasachi Ruj <ruj.sabya@gmail.com>
Date: Thu, 10 Mar 2011 18:47:54 +0530
Message-ID: <AANLkTinq_EaKkU73OPGMjfFk=PR_y85z4pN9aaAozkft@mail.gmail.com>
Subject: Strange behavior if I am declaring a struct String_vector variable
To: user@zookeeper.apache.org
Content-Type: text/plain; charset=ISO-8859-1

I have two programs "trysample.cpp" and "sample.cpp". trysample.cpp
calls execv to invoke "sample", that is, compiled output of "sample.cpp".

sample.cpp simply prints the command line arguments passed to it.

The strange thing is if I am declaring a "struct String_vector"
variable in "trysample.cpp", the arguments received by sample.cpp
becomes wrong. If I am passing 3 arguments, it is showing us 5
arguments have been passed. But if I just comment the "struct
String_vector s;" part, it works fine!

Any idea?

I am giving code for both programs:

sample.cpp
=========
#include<stdio.h>
#include<unistd.h>
#include<stdlib.h>

int main(int argc, char *argv[])
{
  printf ("Number of arugments received: %d\n", argc);
  for (int i = 0; i < argc; i++) {
    printf("%s\n", argv[i]);
  }
}


trysample.cpp
=========
#include <unistd.h>
#include <stdlib.h>
#include <errno.h>
#include "zookeeper.h"


int main(int argc, char *argv[])
{
  struct String_vector s;
  int pid = fork();
  if (pid == 0) {
    char * argv[] =
{"/var/www/vhosts/apps.w/subdomains/sr.c/httpdocs/c/zookeeper/tests/sample",
"aaa", "ddd"};
    execv("/var/www/vhosts/apps.w/subdomains/sr.c/httpdocs/c/zookeeper/tests/sample",
argv);
    printf("returned error! %d\n", errno);
  }
}


--
Sabyasachi