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From: "Jack Krupansky" <jack@basetechnology.com>
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Subject: Re: What is C*?
Date: Thu, 24 Jul 2014 08:38:50 -0400
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Jim, by the way, what exactly does =E2=80=9CC.=E2=80=9D mean in your =
name? I mean, it=E2=80=99s so ambiguous that it could mean anything!

Or is this an example of using a regular expression (you have a =
two-letter last name?) as opposed to C* using a traditional wildcard =
=E2=80=9Cglob=E2=80=9D?!

Maybe =E2=80=9CC*=E2=80=9D should be =E2=80=9CC.*=E2=80=9D.

Or maybe some people would prefer C8  or C7a=E2=80=93 at least that =
would have a chance of returning narrower Google search results than =
searching for =E2=80=9CC*=E2=80=9D.

-- Jack Krupansky

From: Mark Reddy=20
Sent: Thursday, July 24, 2014 4:04 AM
To: user@cassandra.apache.org=20
Subject: Re: What is C*?

Yes you are correct, Cassandra is often abbreviated as C*. With most =
languages and applications being referenced by their acronym / =
abbreviation, I guess you just have to pick one that is available. I =
assume if someone creates a new language and wants to name it C*, they =
will see that it is taken and avoid the conflict.=20


Mark


On Wed, Jul 23, 2014 at 11:50 PM, jcllings <jcllings@gmail.com> wrote:

  Keep seeing refs to C*.

  I assume that C* =3D=3D Cassandra?  IMHO not a good ref to use what =
with C,
  C++, C#.  A language called C* can't be far behind assuming it doesn't
  already exist.
  ;-)

  Jim C.


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<HTML><HEAD></HEAD>
<BODY dir=3Dltr>
<DIV dir=3Dltr>
<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: 'Calibri'; COLOR: #000000">
<DIV>Jim, by the way, what exactly does =E2=80=9CC.=E2=80=9D mean in =
your name? I mean, it=E2=80=99s so=20
ambiguous that it could mean anything!</DIV>
<DIV>&nbsp;</DIV>
<DIV>Or is this an example of using a regular expression (you have a =
two-letter=20
last name?) as opposed to C* using a traditional wildcard =
=E2=80=9Cglob=E2=80=9D?!</DIV>
<DIV>&nbsp;</DIV>
<DIV>Maybe =E2=80=9CC*=E2=80=9D should be =E2=80=9CC.*=E2=80=9D.</DIV>
<DIV>&nbsp;</DIV>
<DIV>Or maybe some people would prefer C8&nbsp; or C7a=E2=80=93 at least =
that would have=20
a chance of returning narrower Google search results than searching for=20
=E2=80=9CC*=E2=80=9D.</DIV>
<DIV>&nbsp;</DIV>
<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: 'Calibri'; COLOR: =
#000000">-- Jack=20
Krupansky</DIV>
<DIV=20
style=3D'FONT-SIZE: small; TEXT-DECORATION: none; FONT-FAMILY: =
"Calibri"; FONT-WEIGHT: normal; COLOR: #000000; FONT-STYLE: normal; =
DISPLAY: inline'>
<DIV style=3D"FONT: 10pt tahoma">
<DIV>&nbsp;</DIV>
<DIV style=3D"BACKGROUND: #f5f5f5">
<DIV style=3D"font-color: black"><B>From:</B> <A =
title=3Dmark.reddy@boxever.com=20
href=3D"mailto:mark.reddy@boxever.com">Mark Reddy</A> </DIV>
<DIV><B>Sent:</B> Thursday, July 24, 2014 4:04 AM</DIV>
<DIV><B>To:</B> <A title=3Duser@cassandra.apache.org=20
href=3D"mailto:user@cassandra.apache.org">user@cassandra.apache.org</A> =
</DIV>
<DIV><B>Subject:</B> Re: What is C*?</DIV></DIV></DIV>
<DIV>&nbsp;</DIV></DIV>
<DIV=20
style=3D'FONT-SIZE: small; TEXT-DECORATION: none; FONT-FAMILY: =
"Calibri"; FONT-WEIGHT: normal; COLOR: #000000; FONT-STYLE: normal; =
DISPLAY: inline'>
<DIV dir=3Dltr>Yes you are correct, Cassandra is often abbreviated as =
C*. With=20
most languages and applications being referenced by their acronym /=20
abbreviation, I guess you just have to pick one that is available. I =
assume if=20
someone creates a new language and wants to name it C*, they will see =
that it is=20
taken and avoid the conflict.=20
<DIV>&nbsp;</DIV>
<DIV>&nbsp;</DIV>
<DIV>Mark</DIV></DIV>
<DIV class=3Dgmail_extra><BR><BR>
<DIV class=3Dgmail_quote>On Wed, Jul 23, 2014 at 11:50 PM, jcllings =
<SPAN=20
dir=3Dltr>&lt;<A href=3D"mailto:jcllings@gmail.com"=20
target=3D_blank>jcllings@gmail.com</A>&gt;</SPAN> wrote:<BR>
<BLOCKQUOTE class=3Dgmail_quote=20
style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc =
1px solid">Keep=20
  seeing refs to C*.<BR><BR>I assume that C* =3D=3D Cassandra?&nbsp; =
IMHO not a good=20
  ref to use what with C,<BR>C++, C#.&nbsp; A language called C* can't =
be far=20
  behind assuming it doesn't<BR>already exist.<BR>;-)<BR><BR>Jim=20
C.<BR><BR></BLOCKQUOTE></DIV>
<DIV>&nbsp;</DIV></DIV></DIV></DIV></DIV></BODY></HTML>

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