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From: Flavio Junqueira <fpjunqueira@yahoo.com.INVALID>
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Subject: Re: problem with Running zookeeper C client on a virtual machine!
Date: Fri, 3 Jul 2015 12:58:24 +0100
References: 
 <E162045FC81D934BB77E1F41A97B1B718D52DCE9@nkgeml511-mbx.china.huawei.com>
To: user@zookeeper.apache.org
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 <E162045FC81D934BB77E1F41A97B1B718D52DCE9@nkgeml511-mbx.china.huawei.com>

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It sounds right that the client shouldn't exit and generate a connection =
loss event instead. But, I don't understand why you're messing up with =
the system time, what is it that you're trying to achieve?

-Flavio

> On 03 Jul 2015, at 09:49, Wangyinwen <wangyinwen@huawei.com> wrote:
>=20
> Hi!
> =20
> I run zookeeper C client on a virtual machine=EF=BC=88zookeeper =
version: 3.4.6, OS: Win7=EF=BC=89, when I roll back system time
> to an earlier time(e.g. current time is 11:56:56, I change system time =
to 11:56:30), the client process will print a message
> "(0x4a4):ZOO_ERROR@handle_socket_error_msg@1723: =
<mailto:%22(0x4a4):ZOO_ERROR@handle_socket_error_msg@1723:> Sock et =
[9.64.253.228:2181] zk retcode=3D-4, errno=3D32(Broken pipe): failed =
while receiving a server response"
> then client process exit. I wander to see what reason may cause ZK =
client exit,
> and how can I make the client process don=E2=80=99t exit but just post =
a session timeout event!
> =20
> =20
> Thank you!
> =20
> =20
> =20
> =20
>=20
> =E7=8E=8B=E8=83=A4=E6=96=87 00171980
> 2012=E5=AE=9E=E9=AA=8C=E5=AE=A4-=E4=B8=AD=E5=A4=AE=E8=BD=AF=E4=BB=B6=E9=99=
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=E8=BD=AF=E4=BB=B6LAB=EF=BC=89
> =E6=89=8B=E6=9C=BA=EF=BC=9A18857136398
> =E5=BA=A7=E6=9C=BA=EF=BC=9A057163024
> =E5=BA=A7=E4=BD=8D=EF=BC=9A=E6=9D=AD=E5=B7=9E=E7=A0=94=E7=A9=B6=E6=89=80=
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> =
=E5=88=86=E5=B8=83=E5=BC=8F=E8=BD=AF=E4=BB=B6LAB=E6=8A=80=E6=9C=AF=E6=B2=99=
=E9=BE=99=EF=BC=9Ahttp://3ms.huawei.com/hi/group/2028451 =
<http://3ms.huawei.com/hi/group/2028451>

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