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Date: Thu, 15 Aug 2013 12:27:33 -0700 (PDT)
From: Russ Lavoie <ussray_00@yahoo.com>
Reply-To: Russ Lavoie <ussray_00@yahoo.com>
Subject: Re: Dynamically Adding nodes to ZK Ensemble
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The main reason why I ask, is because I need the ability to dynamically add=
 ZK nodes to the ensemble. =A0Is there a supported way to do this in 3.4.5?=
=0A=0AThanks,=0A=0ARuss=0A=0A=0A________________________________=0A From: F=
lavio Junqueira <fpjunqueira@yahoo.com>=0ATo: user@zookeeper.apache.org =0A=
Cc: Russ Lavoy <ussray_00@yahoo.com> =0ASent: Thursday, August 15, 2013 9:1=
3 AM=0ASubject: Re: Dynamically Adding nodes to ZK Ensemble=0A =0A=0AHopefu=
lly it is clear that I tried to say long, not log lists.=A0 :-)=0A=0A-Flavi=
o=0A=0AOn Aug 15, 2013, at 3:07 PM, Flavio Junqueira <fpjunqueira@yahoo.com=
> wrote:=0A=0A> There are log lists of patches available and issues for 3.5=
.0. There are only 7 blockers currently marked, though. Until we decide wha=
t to do with all those, we won't have a release. The bottom line is that we=
 don't have a date, even though the general feeling is that we would like t=
o have it soon. The are important features lined up for 3.5.0. It viable to=
 have 3.4.6 shortly, though.=0A> =0A> -Flavio=0A> =0A> =0A> On Aug 14, 2013=
, at 12:42 AM, Deepak Jagtap <deepak.jagtap@maxta.com> wrote:=0A> =0A>> Hi =
Russ,=0A>> =0A>> This presentation gives brief idea about zookeeper cluster=
 reconfig=0A>> mechanism:=0A>> http://www.slideshare.net/Hadoop_Summit/dyna=
mic-reconfiguration-of-zookeeper=0A>> =0A>> zookeeper 3.5.0 source has zkCl=
i.sh utility which supports reconfig command=0A>> to=0A>> dynamically recon=
figure the cluster.=0A>> =0A>> Regards,=0A>> Deepak=0A>> =0A>> =0A>> =0A>> =
=0A>> On Tue, Aug 13, 2013 at 12:49 PM, Russ Lavoy <ussray_00@yahoo.com> wr=
ote:=0A>> =0A>>> Hello,=0A>>> =0A>>> I would like to add ZK nodes dynamical=
ly to an ensemble.=A0 I have seen=0A>>> https://issues.apache.org/jira/brow=
se/ZOOKEEPER-107 but I do not see any=0A>>> documentation on how to do this=
.=0A>>> =0A>>> Can anyone give me some insight?=0A>>> =0A>>> Thanks=0A> 
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