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From "David N Bertoni/CAM/Lotus" <David_N_Bert...@lotus.com>
Subject Re: XSLT output question
Date Thu, 20 Apr 2000 17:26:29 GMT

Well it's not doing that to indicate an error -- the processor is required
to do that.  The XSLT specification requires that the processor treat
elements with undeclared namespaces as literal result elements.  Since
literal result elements are copied to the output xml, you get back exactly
what you put in -- the stylesheet.


                    Eric Hodges                                                          
                    <harmony2@swb        To:     general@xml.apache.org, xalan-dev@xml.apache.org
                    ell.net>             cc:     (bcc: David N Bertoni/CAM/Lotus)     
                                         Subject:     Re: XSLT output question           
                    11:38 AM                                                             
                    respond to                                                           

----- Original Message -----
From: David N Bertoni/CAM/Lotus <David_N_Bertoni@lotus.com>
To: <general@xml.apache.org>; <xalan-dev@xml.apache.org>
Sent: Thursday, April 20, 2000 9:42 AM
Subject: Re: XSLT output question

> Generally, when you just get the stylesheet back from the transform, it
> means that the XSL namespace is incorrect in the stylesheet.

That seems like an obtuse way to indicate that the namespace is incorrect.

>  The proper
> value is "http://www.w3.org/1999/XSL/Transform.

Let me try that real quick.

That was it.  I also had to remove the "result-ns" attribute, too.

> By the way, this question really belongs on the Xalan list -- you're
> get quicker responses to your questions there.

OK, I'll go look for that list.

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