Return-Path: Mailing-List: contact general-help@xml.apache.org; run by ezmlm Delivered-To: mailing list general@xml.apache.org Received: (qmail 29534 invoked from network); 25 Mar 2000 15:09:44 -0000 Received: from chmls06.mediaone.net (24.128.1.71) by locus.apache.org with SMTP; 25 Mar 2000 15:09:44 -0000 Received: from jabr (jabr.ne.mediaone.net [24.218.25.27]) by chmls06.mediaone.net (8.8.7/8.8.7) with SMTP id KAA19468 for ; Sat, 25 Mar 2000 10:09:38 -0500 (EST) From: "Jonathan Borden" To: Subject: RE: XSLT selection by node contents Date: Sat, 25 Mar 2000 09:59:12 -0500 Message-ID: <005701bf966a$ae1206e0$1b19da18@ne.mediaone.net> MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook 8.5, Build 4.71.2173.0 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2919.6600 In-Reply-To: <016701bf95e3$61f7ae40$6a1010ac@rosetta.zon> Importance: Normal X-Spam-Rating: locus.apache.org 1.6.2 0/1000/N Sean Kelly [mailto:kelly@ad1440.net] > I want to write XSLT that looks like: > > > Do one thing. > > > Do another thing > > > The question is ... what do I put in for ??? that selects the value of the > text node of the location node? Or is this even the right way to proceed? > I would try: starts-with(.,'ioop') . being the way to express the current node. General XSL questions can also be directed to the XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list Jonathan Borden