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From Brian Dupras <bri...@centera.com>
Subject RE: xslt with existing DOM nodes: HIERARCHY_REQUEST_ERR
Date Tue, 18 Jan 2000 21:15:24 GMT
> The error I get now is:
>  "org.apache.xerces.dom.DOMExceptionImpl: HIERARCHY_REQUEST_ERR"

Found the trouble: It seems that I can only perform a transform against the
whole document, not just a single node and its children.  Is this spec'd
behavior?

Brian

> -----Original Message-----
> From: Brian Dupras [mailto:briand@centera.com]
> Sent: Tuesday, January 18, 2000 9:59 AM
> To: Xml-Apache (E-mail)
> Subject: xslt with existing DOM nodes: HIERARCHY_REQUEST_ERR
> 
> 
> Thanks for all the help I'm getting here with the apache xml/xsl
> implementations.
> 
> I'm trynig to get (xml Node) + (xsl Node) => (xml Node) 
> working, but I keep
> getting an error.  Thanks Scott for the XercesLiaison() fix - 
> it got me half
> way.
> 
> The error I get now is:
>  "org.apache.xerces.dom.DOMExceptionImpl: HIERARCHY_REQUEST_ERR"
> 
> I'm sending in two DOM nodes and want to receive a DOM node in return.
> Following is a sample.
> 
> Brian
> 
> 
> Code snippets:
> 
> private Element processElement(Element xmlelemTarget, 
>                                Element xmlelemXSLT) 
>                                throws SAXException 
> {
> 	Document xmldocResult = new DocumentImpl();
> 	xsltProcessor.process(	new XSLTInputSource(xmlelemTarget), 
> 					new 
> XSLTInputSource(xmlelemXSLT), 
> 					new 
> XSLTResultTarget(xmldocResult)
> 					);
> 	return xmldocResult.getDocumentElement();
> }
> 
> 
> domParser =
> (DOMParser)Class.forName("org.apache.xerces.parsers.DOMParser"
> ).newInstance(
> );
> 
> xsltProcessor = XSLTProcessorFactory.getProcessor(new
> org.apache.xalan.xpath.xdom.XercesLiaison());
> 
> 
> thexml = parser.parse(fname).getDocument().getDocumentElement();
> thexsl = parser.parse(fname).getDocument().getDocumentElement();
> 
> NodeList nl = thexml.getElementsByTagName("component");
> ...
> thexmlElement = (Element)nl.item(i);
> 
> //throws exception HIERARCHY_REQUEST_ERR:
> Element result = processElement(thexmlElement, thexsl);
> 
> 
> 
> 
> 
> The xml Node (Element) looks like this:
> <component>
>   <resource rid='abdcedfghi127_nons'/>
>   <type rid='abdcedfghi002_nons'/>
>   <params/>
> </component>
> 
> 
> The xsl Node (Document Element) looks like this:
> <?xml version="1.0"?>
> 
> <xsl:stylesheet	
> 	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> 	xmlns:pp="http://medwired.com/namespaces/practiceportal/1.0"
> 	xmlns:xlink='http://www.w3.org/XML/XLink/0.9'
> 	exclude-result-prefixes="pp xlink"
> 	>
> 	<xsl:output method="xml" indent="yes" 
> omit-xml-declaration="yes" />
> 	
> 	<span>
> 		testing
> 	</span>
> </xsl:stylesheet>
> 
> 
> Brian Dupras
> Centera Information Systems, Inc.
> phone	303.939.0200 x294
> fax	303.939.0111
> web	http://www.centera.com
> email	briand@centera.com
> 

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