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From Nirmal Mukhi <>
Subject Re: Service Name's soap:address location
Date Wed, 05 Nov 2003 17:18:49 GMT

You can modify the service endpoint in the WSDL definition 
programmatically. Here is some sample code which should do this (not 
compiled or tested, but it should be approximately correct). This uses the 
standard WSDL API being defined in JSR110 (see for the 
reference implementation).

WSDLFactory factory = WSDLFactory.newInstance();
WSDLReader reader = factory.newWSDLReader();
Definition def = reader.readWSDL(null,"sample.wsdl");
Service service = def.getService(new QName("foo","bar"); // accesses 
service named foo:bar
List extElements = service.getExtensibilityElements();
SOAPAddress address = (SOAPAddress) extElements.get(0); // this assumes 
that there is only one extensibility element under <service>, viz. 

Now the definition (def) can be used by WSIF to create a WSIFService that 
will attempt to invoke the service whose SOAP endpoint is http://newURI.

Hope that helps,

"David Seager" <>
10/30/2003 08:13 AM
Please respond to wsif-user
        Subject:        Re: Service  Name's soap:address location

Hi Leo,

That WSDL shouldn't execute correctly from a remote client, as localhost
will resolve to the machine it's being run on. The best way is to store 
WSDL on a web server on the remote server machine, with the location set
with the remote server's hostname. Then point the client at the WSDL on 
remote server.

However, if you know which provider gets used, there are methods on some 
override the location URL. In the WSIFPort_ApacheAxis class, in the Apache
Axis provider, there is a setEndPoint method which will do the trick. Here
is my code which changes the URL to something else:

      String wsdlLocation = "http://localhost:8080/axis/Expire.jws?wsdl";
      WSIFServiceFactory factory = WSIFServiceFactory.newInstance();
      WSIFService service = factory.getService(wsdlLocation, null, null,
null, null);
      WSIFPort p = service.getPort();

      // override port
      WSIFPort_ApacheAxis pA = (WSIFPort_ApacheAxis)p;
      pA.setEndPoint(new URL("http://localhost:8081/axis/Expire.jws"));

      o = p.createOperation(operation);

      m1 = o.createInputMessage();
      m2 = o.createOutputMessage();
      m3 = o.createFaultMessage();

      boolean ok = o.executeRequestResponseOperation(m1, m2, m3);

The WSDL referenced defines the Expire service to be at
http://localhost:8080/axis/Expire.jws. However, the above code sends the
request to the address in the override call. This only works if the
provider being used is Apache Axis.


David Seager
IBM Hursley

                      "Leo Barcenas"   
                      <        To: 
                      >                        cc:    
                                               Subject:  Service  Name's 
soap:address location 
                      30/10/2003 11:33   
                      Please respond to   


I would like to ask about the WSDL file used in WSIF. In particular,
the soap:address location of the Service name.
I'm just quiet puzzled that some of the files I saw is written the one

  <service name="ServiceNM">
    <port name="SoapPort" binding="tns:SoapBinding">
      <soap:address location="http://localhost/WSDL/iLON100.WSDL" />

Considering the above WSDL syntax, will this be able to correctly execute
from a remote client? If not, is there a way that you can change
into the IP address of the server where the web service is located during
runtime? I've tried it in VB.NET by using the WebReference's URL property
and replacing "localhost" to the server's IP address.

Hoping for your answer.

Many thanks.


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