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From Silvestre Losada <silvestre.los...@gmail.com>
Subject Re: Ruta partofneq
Date Fri, 20 Feb 2015 08:17:46 GMT
HI again,

Now I'm running into this problem
DECLARE T1;
"A B C D" -> T1;
"B" -> T1;
"C D" -> T1;
"D" -> T1;

(T1{-> UNMARKALL(T1)}){PARTOFNEQ(T1)};

The ouput is
"A B C D" -> T1;
"D" -> T1;

I suspect that this is because D is part of "A B C D" and "C D"

Im using lastest version in trunk.


Kind regards

On 14 February 2015 at 09:29, Silvestre Losada <silvestre.losada@gmail.com>
wrote:

> Thanks Peter,
>
>
> It seems to work.
>
> On 13 February 2015 at 22:18, Peter Kl├╝gl <pkluegl@uni-wuerzburg.de>
> wrote:
>
>> This should work just fine and should remove both contained annotations.
>>
>> I just tested it with the current trunk and the following script:
>>
>> DECLARE T1;
>> "A B" -> T1;
>> "B" -> T1;
>> "B" -> T1;
>>
>> (T1{-> UNMARK(T1)}){PARTOFNEQ(T1)};
>>
>> If applied on the test "A B", only the largest annotation remains.
>>
>> Can you test it with the current trunk in case I fixed the bug a few
>> minutes ago by accident. If not, can you give me more information about the
>> context of your rule?
>>
>> Best,
>>
>> Peter
>>
>> Am 12.02.2015 um 10:12 schrieb Silvestre Losada:
>>
>>  I dont know if this is a bug or if it is wokring well. I have the
>>> following
>>> annotations.
>>>
>>> AnnotationA
>>>       begin:0
>>>       ends:8
>>>        id:1
>>> AnnotationA
>>>       begin:4
>>>       ends:8
>>>        id:2
>>> AnnotationA
>>>       begin: 4
>>>       ends:8
>>>        id:3
>>>
>>> Then if apply the following ruta
>>>
>>> (AnnotationA{-> UNMARK(AnnotationA)}){PARTOFNEQ(AnnotationA)};
>>>
>>> The output is
>>> AnnotationA
>>>       begin:0
>>>       ends:8
>>>        id:1
>>> AnnotationA
>>>       begin: 4
>>>       ends:8
>>>        id:3
>>>
>>> I expect that annotations with id 2 and 3 will be removed. Is there any
>>> way
>>> to remove both
>>>
>>> Kind regards
>>>
>>>
>>
>

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