Hi
I would want to request a jsp page from another page as following
http://domain.com/folder1/abcd.jsp to http://domain.com/folder2/xyz.jsp
Using Javascript / action
But I need both the JSP pages hidden in the URL ...... :(
With web.xml configurations should each configurations need to be done ?
I also have roughly 300+ similar pages across folder1 /folder 2
Request - Responding
With regards
Karthik
-----Original Message-----
From: Konstantin Kolinko [mailto:knst.kolinko@gmail.com]
Sent: Thursday, April 01, 2010 12:51 AM
To: Tomcat Users List
Subject: Re: Hide JSP name using web.xml
2010/3/31 Karthik Nanjangude <karthik.nanjangude@xius-bcgi.com>:
> Let us say I have
>
> http://domain.com/folder1/abcd.jsp ==> http://domain.com/folder1/
> http://domain.com/folder2/xyz.jsp ==> http://domain.com/folder2/
> (..)
You want to have requests to http://domain.com/folder1/ to be
processed by http://domain.com/folder1/abcd.jsp. It can be done by
calling
ServletContext.getRequestDispatcher("/folder1/abcd.jsp").forward(request,
response)
The above call can be performed by a Servlet or by a Filter.
E.g. you can use http://tuckey.org/urlrewrite/ or write your own filter.
Best regards,
Konstantin Kolinko
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