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Date: Mon, 1 Jun 2009 13:55:14 +0800
Message-ID: <30d841e90905312255sb4cc41rc9ea40664d85c2ce@mail.gmail.com>
Subject: How to do with response.sendError() after the ServletOutputStream is
	established?
From: =?GB2312?B?wffLrtL0?= <aoingl@gmail.com>
To: users@tomcat.apache.org
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HI,ALL:

Servlet code(deployed on Tomcat server):
    private void execute(HttpServletRequest req, HttpServletResponse
resp) throws ServletException, IOException {
           try {
                    int count = 0;
                    while(count< 1000000){
                         out.write(97); // writes 'a' to client
                         count++;
                         if(count == maxcount()){
                             throw new Exception("errors.");
                         }
                    }
            }catch(Exception e){
                 resp.sendError(605);
                 return;
            }
    }

    private int maxcount(){
         return 99999;// or return 15;
    }

Client code:

        URL url = new URL(urlAddress);
        HttpURLConnection conn = (HttpURLConnection)url.openConnection();
	conn.setDoInput(true);
	conn.setUseCaches(false);
	conn.setAllowUserInteraction(false);
	conn.connect();
	InputStream input = null;
        try {
		input = conn.getInputStream();
		int count=0;
		while((input.read()) != -1){
			count++;
		}
		System.out.println("total read is: " + count);
	} catch (IOException e) {
                int code = conn.getResponseCode();
		System.out.println("Response code is: " + code);
	}finally{
           Closer.close(input);
        }

when the maxcount() returns 15, the exception is thrown out before the
first buffer is flushed, then client can get the response code of: 605
but when the maxcount() returns 99999, the exception is thrown out
after some buffers flushes, so the client can not get the exception
anymore, the response code is 200.

so, if I want to get the exception during the data transferring in the
client, do you guys have any idea hot to do that?

Thanks and Best Regards.

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