Hello
Update
There seems to be another set of outputs. If I do not run the web first and
just start it and then run my ajax app, I execute the call to the webapp,
but there is no parameter, even though I check both
XMLHttpRequest.open(a,b,c) and XMLHttpRequest.send(query). This is a check
right before, I know it the proper url. This sort of explains the initial
problem cited below, but not how I loose the parameter. Ideas2? Thanks.
cpanon wrote:
>
> Hello
> I trying to access an running webapp that itself works fine. I can see
> the results of the app within the output of my IDE when I just run the app
> separately. Problem is I am trying to test an ajax app and when I execute
> the XMLHttpRequest.send(query) after proper setup with a known parameter I
> see the app just re-executing the same page with same parameter that it
> had; not the one in my ajax call. It is as if my XMLHttpRequest.send()
> was just executing a refresh. Obviously I then dont get anything aback.
> I have tried from a different browser window. This is not exotic, just
> self testing an ajax app against a localhost webapp. Ideas? tia.
>
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