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Subject: RE: web.xml, <url-pattern>
Date: Mon, 12 Sep 2005 23:44:18 +0200
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From: =?iso-8859-1?Q?Trond_Hersl=F8v?= <trond.herslov@GOTOGATE.no>
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Hi
Thanks a lot for clarifying that. At the bottom you say: the servlet spec.
Im reading "The J2EE 1.4 Tutorial", for Sun Java System Application Server =
Platform. Isnt Tomcat the referential project for this technologi?

Can you please be so kind and explain what the servlet spec. has to do with=
 configuring the deployment descriptor.

Could you give me a link to the servlet spec?

Thanks again,
Trond



-----Original Message-----
From: Mark Thomas [mailto:markt@apache.org]=20
Sent: 12. september 2005 20:17
To: Tomcat Users List
Subject: Re: web.xml, <url-pattern>

Trond Hersl=F8v wrote:
> But, if I try using wildcards, eg. <url-pattern>/*foxer</url-pattern it d=
oesent work anymore.

Correct. Wildcards are not supported for mapping paths. Read the=20
servlet spec for more details.

> If I try to map the servlet so that it seems like a jsp-page <url-pattern=
>/foxer.jsp</url-pattern>, it doesn't work at all.

Also correct. There is a server-wide mapping for *.jsp (wild cards are=20
supported for extension mapping) in $TOMCAT_HOME/conf/web.xml

> In the book I also read that I should be able to access the servlet even =
if it's not mapped up in web.xml. http://www.mymachine.no/servlet/foxer Ofc=
ourse this does also not work.

This is using the invoker servlet, which is disabled by default.

> Who can explain how to use the <url-pattern> and maybe tell me where I ca=
n find some documentation on how to configure web.xml

The servlet spec.



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