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From "Brereton, Stephen" <stephen.brere...@york.gov.uk>
Subject RE: can anyone make sense of this
Date Mon, 13 Jun 2005 17:54:39 GMT
how exactly does the servlet get called? Are you using the web server?

-----Original Message-----
From: teknokrat [mailto:teknokrat@yahoo.com]
Sent: 13 June 2005 18:44
To: tomcat-user@jakarta.apache.org
Subject: Re: can anyone make sense of this


Brereton, Stephen wrote:
> That's just your Tomcat service running. It does take a few moments to get
> started - that's just Java getting going. If your task manager isn't
running
> to show 'all users', you might well not see the service running
> 
> -----Original Message-----
> From: teknokrat [mailto:teknokrat@yahoo.com]
> Sent: 13 June 2005 17:52
> To: tomcat-user@jakarta.apache.org
> Subject: can anyone make sense of this
> 
> 
> I have the latest tomcat 5.0 installed on windows server 2003 with java 
> 5. I run startup.bat and call a servlet that hits a jboss instance 
> remotely. Looking through the connection events with TDIMon ( from 
> www.sysinternals.com ) I notice that a process tomcat5.exe sends a UDP 
> datagram on port 137 to the remote server just before creating the TCP 
> connection. Now, what I don't understand is
> 
> 1. All the other network events are created by the process java.exe. I 
> am not running any tomcat.exe - in fact I have deleted them. There is no 
> tomcat5.exe process in the task manager so what is going on here.
> 
> 2. this is a very slow. tomcat5.exe makes about three udp datagrams and 
> takes about 2 seconds.
> 
> 3. I realise that this may be a jboss issue but if anyone can confirm ro 
> deny this I would appreciate this
> 
> thanks
> 
> 
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Thats what I thought. But i am not running the service, only using 
startup.bat. Also I have renamed the tomcat5.exe. In the task manager I 
have show processes for all users enabled.


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Council by this e-mail and the City of York Council accepts no
responsibility whatsoever for its contents.  Please note that any reply to
this email may be screened.

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