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From "Shapira, Yoav" <Yoav.Shap...@mpi.com>
Subject RE: How to get the offending uri when handling a 404 error?
Date Thu, 03 Jun 2004 13:14:18 GMT

Hi,

>-----Original Message-----
>From: Ariel Valentin [mailto:asvb278@hotmail.com]
>Sent: Wednesday, June 02, 2004 10:19 PM
>To: tomcat-user@jakarta.apache.org
>Subject: RE: How to get the offending uri when handling a 404 error?
>
>I believe the ErrorData class only holds 500 errors.

Where did you get that impression?

Yoav

>To get the 404 url use the getRequestURL method of HttpServletRequest:
>request.getRequestURL()
>That returns a string representation of the URL that generated the
request.
>Your might also consider setting up a filter that recognizes and logs
those
>bad requests.
>
>Hope that helps,
>
>Mr. Ariel S. Valentin
>mailto: asvb278@hotmail.com
>
>
>
>
>>From: "Mike Curwen" <gb_dev@gb-im.com>
>>Reply-To: "Tomcat Users List" <tomcat-user@jakarta.apache.org>
>>To: "'Tomcat Users List'" <tomcat-user@jakarta.apache.org>
>>Subject: RE: How to get the offending uri when handling a 404 error?
>>Date: Wed, 2 Jun 2004 09:37:48 -0500
>>
>>I got a related question:
>>
>>Even if you fail to set the isErrorPage directive, would you still be
>>able to access the information through the request attributes?
>>
>>such as:
>>javax.servlet.error.request_uri
>>
>>
>>
>> > -----Original Message-----
>> > From: Shapira, Yoav [mailto:Yoav.Shapira@mpi.com]
>> > Sent: Wednesday, June 02, 2004 7:50 AM
>> > To: Tomcat Users List
>> > Subject: RE: How to get the offending uri when handling a 404
error?
>> >
>> >
>> >
>> > Hi,
>> > Does your 404.jsp have the isErrorPage directive set to true?
>> >
>> > Yoav Shapira
>> > Millennium Research Informatics
>> >
>> >
>> > >-----Original Message-----
>> > >From: Joseph Shraibman [mailto:jks@selectacast.net]
>> > >Sent: Tuesday, June 01, 2004 7:57 PM
>> > >To: tomcat-user@jakarta.apache.org
>> > >Subject: How to get the offending uri when handling a 404 error?
>> > >
>> > >I put this in my web.xml:
>> > >
>> > ><error-page>
>> > ><error-code>404</error-code>
>> > ><location>/404.jsp</location>
>> > ></error-page>
>> > >
>> > >... and this in 404.jsp:
>> > >
>> > >ErrorData ed = pageContext.getErrorData();
>> > >if (ed != null) url = ed.getRequestURI() ;
>> > >
>> > >but it throws:
>> > >
>> > >StandardWrapperValve[jsp]: Servlet.service() for servlet jsp threw
>> > >exception java.lang.NullPointerException
>> > >java.lang.NullPointerException
>> > >         at
>> > >javax.servlet.jsp.PageContext.getErrorData(PageContext.java:514)
>> > >         at org.apache.jsp._404_jsp._jspService(_404_jsp.java:102)
>> > >         at
>> > >org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
>> > >         at
>> > javax.servlet.http.HttpServlet.service(HttpServlet.java:810)
>> > >         at
>> > >org.apache.jasper.servlet.JspServletWrapper.service(JspServle
>> > tWrapper.j
>> > ava:
>> > >298)
>> > >         at
>> > >org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServle
>> > t.java:292
>> > )
>> > >         at
>> > >org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
>> > >
>> > >(this is with tomcat 5.0.24)
>> > >
>> > >So how can I get the url the the user tried to request?
>> > >
>> >
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