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From "Jonathan Eric Miller" <jemil...@uchicago.edu>
Subject Default servlet mapping not working in Tomcat 5.0.16?
Date Fri, 12 Dec 2003 18:23:24 GMT
I'm using Tomcat 5.0.16 and I'm trying to make it so that if a user enters a
path like, http://myserver/myapp it runs a default servlet for that path.

According the the Servlet 2.4 spec, you can do this by mapping "/" to a
servlet. However, for me, it's just printing out a directory listing of the
/myapp directory when I try it (on a side note, how do you globally disable
directory browsing?).

I'm using a web.xml similar to the following.

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee web-app_2_4.xsd"
version="2.4">
<servlet>
<servlet-name>myservlet</servlet-name>
<servlet-class>mypackage.MyServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>myservlet</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/servlet/myservlet</url-pattern>
<url-pattern>/servlet/myservlet/*</url-pattern>
</servlet-mapping>

Also, I have something similar to the following in my server.xml.

<Context path="/myapp" docBase="myapp" debug="0" reloadable="true">

Any ideas?

I can do what I want to do using an index.jsp with a redirect, but, I would
like to avoid having it do a redirect if possible.

Jon


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