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From Kwok Peng Tuck <pengt...@makmal.net>
Subject Re: Database setup? - SOLVED
Date Mon, 02 Jun 2003 02:36:31 GMT
Yes it does have to be in order :) . Check the dtd that it references.

Terje Hopsø wrote:

>Thanks!!
>
>It was out of order. Now it start without errors. I was not aware of that it
>had to be in a spesific order.
>
>- Terje
>
>
>-----Original Message-----
>From: Brian Buchanan [mailto:brianbuchanan@interfast.ca] 
>Sent: 29. mai 2003 14:15
>To: Tomcat Users List
>Subject: RE: Database setup?
>
>
>
>The order of the elements in the web.xml file must be in a specific order.
>
>As the error message states, they must appear in this order:
>(icon?,display-name?,description?,distributable?,context-param*,filter*,fil
>ter-mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mappin
>g*,welcome-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,se
>curity-constraint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-loca
>l-ref
>
>You probably just have your nested elements out of order.  Perhaps you have
>a <servlet> or <servlet-mapping> before your <context-param> which is
>invalid.
>
>If you want to know more about the format of the web.xml file, you can
>download the servlet specification from Sun here:
>
>http://java.sun.com/products/servlet/download.html
>
>Here's a link to the 2.3 specification
>http://www.jcp.org/aboutJava/communityprocess/final/jsr053/
>
>and refer to chapter 13 - Deployment Descriptor
>
>Once you have that sorted out you can see what next falls out.
>
>I would also recommend that you learn on the latest version of Tomcat
>available which is 4.1.24 right now.
>
>http://jakarta.apache.org/tomcat/
>
>http://jakarta.apache.org/builds/jakarta-tomcat-4.0/release/v4.1.24/
>
>FYI, If you happen to be using Windows I'd also like to offer this advice:
>
>I used to download the .exe version and install it, but I would now
>recommend the .ZIP version as it doesn't "fiddle" with your configuration.
>Sure, getting it to run as a service is a bit trickier, but for development
>the less fiddling the better.
>
>As a zip file I start tomcat from the command line with
>
>SET JAVA_HOME=(whichever jvm I want to use)
>SET CATALINA_HOME=(Whever I unzipped tomcat to)
>%CATALINA_HOME%\bin\startup.bat
>
>Example:
>SET JAVA_HOME=C:\j2sdk1.4.1_02
>SET CATALINA_HOME=C:\jakarta-tomcat-4.1.24
>%CATALINA_HOME%\bin\startup.bat
>
>This way you can also try different JVM's and different tomcat installs
>easily.
>
>Good luck.
>
>._. Brian Buchanan
>
>-----Original Message-----
>From: Terje Hopsø [mailto:tehosubs@online.no]
>Sent: Thursday, May 29, 2003 7:45 AM
>To: 'Tomcat Users List'
>Subject: Database setup?
>
>
>Hi,
>
>I am trying to setup Tomcat according to the book "JavaServer Pages" page
>157. But all I get when starting up tomcat is errors. I also tried JNDI but
>that was less understandable so I will first try this simple setup, which I
>cant understand why failes.
>
>Anyone got a hint on what I have to to?
>
>I have a standard Tomcat 4.1.18 and JSTL installed.
>
>- Terje
>
>
>Here is my setup in web.xml:
>-------------------------
> <context-param>
>  <param-name>
>   javax.servlet.jsp.jstl.sql.DataSource
>  </param-name>
>  <param-value>
>
>jdbc:mysql://db.server.no:3306/myuser,com.mysql.jdbc.Driver,myusername,mypas
>sword
>  </param-value>
> </context-param>
>-------------------------
>The error when starting tomcat is:
>Starting service Tomcat-Standalone
>Apache Tomcat/4.1.18
>29.mai.2003 13:28:37 org.apache.commons.digester.Digester error
>SEVERE: Parse Error at line 28 column 11: The content of element type
>"web-app" must match
>"(icon?,display-name?,description?,distributable?,context-param*,filter*,fil
>ter-mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mappin
>g*,welcome-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,se
>curity-constraint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-loca
>l-ref
>*)".
>org.xml.sax.SAXParseException: The content of element type "web-app" must
>match
>"(icon?,display-name?,description?,distributable?,context-param*,filter*,fil
>ter-mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mappin
>g*,welcome-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,se
>curity-constraint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-loca
>l-ref*)".
>        at
>org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(ErrorHand
>lerWrapper.java:232)
>        at
>org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(ErrorHand
>lerWrapper.java:232)
>        at
>org.apache.xerces.util.ErrorHandlerWrapper.error(ErrorHandlerWrapper.java:17
>3)
>        at
>org.apache.xerces.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:37
>1)
>....
>----------------------------------
>
>In my jsp-file this works fine but I want to put the datasource parameters
>into web.xml instead of each jsp-file where I access a database.
>---
><sql:setDataSource var="ex" scope="application"
> driver="com.mysql.jdbc.Driver"
> url="jdbc:mysql://db.server.no:3306/myuser"
> user="myusername"
> password="mypassword"
>/>
><sql:query var="init"
> dataSource="${ex}"
> sql="select name from adress"
>/>
>
><c:forEach items="${init.rows}" var="row">
> <c:out value="${row.name}" /><br>
></c:forEach>
>---
>
>
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>
>
>  
>


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