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From "John Burgess" <j...@riskdecisions.com>
Subject Re: EXECUTE an external .exe-file (+Parameters) that creates data-filesI want to use later in my servlet
Date Mon, 10 Feb 2003 17:12:30 GMT
I think you'll need the full (absolute) path to the exe.  There is a call in
the servlet api to translate a relative path to an absolute path in the
server's file system but I can't remember what it is.
Otherwise, put data.exe somewhere on the system path and drop the relative
directory part.

----- Original Message -----
From: "Patrick Kosiol" <kosiol@simu.de>
To: "Tomcat Users List" <tomcat-user@jakarta.apache.org>
Sent: Tuesday, January 21, 2003 11:35 AM
Subject: EXECUTE an external .exe-file (+Parameters) that creates
data-filesI want to use later in my servlet


> Hi,
>
> I'm runnung TomCat 4.0.4 and I want to start an external .exe-File.
> My Code:
>
>        String[] runString = {relativeDataPath + "data.exe",
>          parameter0, parameter1, parameter2, parameter3};
>        Process p = Runtime.getRuntime().exec(runString);
>        System.out.println(runString);
>        if(p.waitFor() == 0){
>          ........
>
> The 'data.exe'-File is placed in
> $CATALINA_HOME/webapps/ROOT/relativeDataPath so it should be no problem
> to access this File. The Number of  Parameters etc. is OK.
> But I get the following Error-Message:
>
> java.io.IOException: CreateProcess: 'relativeDataPath'/bfpldata.exe
> parameter0 parameter1 parameter2 parameter3 error=2
>
> error=2 means imho that the File is not found. How can I execute my file
> to do that, what I want. Is it possible that the process can create
> files in the Tomcat folders?
>
>
> Thx
> Patrick
>
>
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