What does your web.xml file contain? For every servlet
in your application, you should have a <servlet>
element and a mapping element.
--- Mark Liu <markliu1989@yahoo.com> wrote:
> I am running Tomcat 4.1.12 on my Windows 2000
> system.
>
> Tomcat runs pretty well. The examples run pretty
> well.
>
> I created an x509 directory under webapps, i.e., I
> have C:\Tomcat4_1_12\webapps\x509 now.
>
> Then I created 2 folders under x509: WEB-INF and
> Test,
> i.e., I have
>
> C:\Tomcat4_1_12\webapps\x509\WEB-INF
>
> and
>
> C:\Tomcat4_1_12\webapps\x509\Test
>
> now.
>
> Under WEB-INF I have web.xml and a folder called
> classes.
>
> i.e., C:\Tomcat4_1_12\webapps\x509\WEB-INF\classes.
>
> I put Marty Hall's ShowParametersPostForm.html under
> Test, and his ShowParameters.class &
> ServletUtilities.class under classes.
>
> I was able to see the ShowParametersPostForm.html
> page
> via this link:
>
>
http://localhost/x509/Test/ShowParametersPostForm.html
>
> But then when I fill up the form and hit submit, I
> always get this:
>
> type Status report
>
> message /x509/servlet/ShowParameters
>
> description The requested resource
> (/x509/servlet/ShowParameters) is not available.
>
> However, if I move the structure to Tomcat's
> examples
> folder, it works great.
>
> Please note that I have changed servlet path
> specified
> in ShowParametersPostForm.html to
>
> <FORM ACTION="../servlet/ShowParameters"
> METHOD="POST">
>
> Also please note that I have added x509 context in
> server.xml under conf, like so:
>
> <!-- Project X509 context -->
> <Context path="/x509" docBase="x509"
> debug="0" reloadable="true"
> privileged="true"/>
>
> I do not understand why it does not work under my
> x509
> directory. I have been trying this for the whole
> day!
>
> Any kind help please?
>
> Thanks a lot.
>
> Mark
>
>
>
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