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From: "Artigas, Ricardo Y." <rya@easycall.net.ph>
To: tomcat-user@jakarta.apache.org
Subject: RE: user admin
Date: Tue, 17 Jul 2001 18:06:25 +0800
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add this line:
<user name=3D"yourusername" password=3D"yourpassword" roles=3D"admin" =
/>


:^)
Ricky Y. Artigas
Analyst/Programmer /
Database Administrator
Information Technology Division
Easycall Communications Phils., Inc.
- Easycall Internet -
418 Arayat St., Mandaluyong City 1550, Philippines
Company Website: http://www.easycall.com.ph
Tel.no: (+632) 5338001 ext.6574
Mobile:(+63) 0917-8951783
Pager:  141-002955
Email: rya@easycall.net.ph


> -------------------------------
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>=20
>=20
> -----Original Message-----
> From:	Cristian Bortolato [SMTP:bortolato@prosa.com]
> Sent:	Tuesday, July 17, 2001 4:23 PM
> To:	'tomcat-user@jakarta.apache.org'
> Subject:	RE: user admin
>=20
> I'm using tomcat 3.2.2, there're tomcat-user.xml defined :
>=20
> <tomcat-users>
>   <user name=3D"tomcat" password=3D"tomcat" roles=3D"tomcat" />
>   <user name=3D"role1"  password=3D"tomcat" roles=3D"role1"  />
>   <user name=3D"both"   password=3D"tomcat" roles=3D"tomcat,role1" />
> </tomcat-users>
>=20
> I've used user tomcat with pass tomcat and all combinations with =
role1 and
> both, but it doesn't open the page.
>=20
>=20
>=20
> -----Original Message-----
> From: Sladky, Jan [mailto:Jan.Sladky@partner.commerzbank.com]
> Sent: Tuesday, July 17, 2001 10:02 AM
> To: 'tomcat-user@jakarta.apache.org'
> Subject: AW: user admin
>=20
>=20
> For tomcat 3.3-m4 change the file conf/admin-users.xml
> =20
> hth
> Jan
>=20
> -----Urspr=FCngliche Nachricht-----
> Von: prs05@prosa.com [mailto:prs05@prosa.com]
> Gesendet am: Dienstag, 17. Juli 2001 09:48
> An: tomcat-user@jakarta.apache.org
> Betreff: user admin
>=20
> Which is the password and the user default for Tomcat admin?
> =20
> How can I Find it and replace?