From aoriglia@calendra.com Thu Nov 2 18:46:46 2000 Return-Path: Mailing-List: contact tomcat-user-help@jakarta.apache.org; run by ezmlm Delivered-To: mailing list tomcat-user@jakarta.apache.org Received: (qmail 32877 invoked from network); 2 Nov 2000 18:46:46 -0000 Received: from unknown (HELO mail.calendra.com) (195.115.144.129) by locus.apache.org with SMTP; 2 Nov 2000 18:46:46 -0000 Received: from louisoncresson ([195.115.144.131]) by mail.calendra.com (Netscape Messaging Server 3.62) with SMTP id 275 for ; Thu, 2 Nov 2000 19:44:42 +0100 Message-ID: <003701c044fd$4311f980$3001a8c0@louisoncresson> From: "Alain Origlia" To: Subject: Changing Root Date: Thu, 2 Nov 2000 19:46:50 +0100 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0034_01C04505.A4BF7E20" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.00.2919.6700 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2919.6700 X-Spam-Rating: locus.apache.org 1.6.2 0/1000/N C'est un message de format MIME en plusieurs parties. ------=_NextPart_000_0034_01C04505.A4BF7E20 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Hi, I use Tomcat3.3 (a fresh nightly build 2000/10/31) in standalone mode, = and I don't succeed in changing the root of the internal 8080 web = server. I declared a new context in the server.xml file: =20 But I still have the default Tomcat Home Page when I ask for = http://localhost:8080 Is it the right way to do this? Is it possible (!)? Is there another = file to configure? Thanks P.S: this used to work with a previous version (3.2beta6) Alain Origlia CALENDRA 135, rue du Dirigeable ZI Les Paluds 13783 AUBAGNE Cedex Tel: +33 (0)4 42 18 69 90 http://www.calendra.com ------=_NextPart_000_0034_01C04505.A4BF7E20 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Hi,
 
I use Tomcat3.3 (a fresh = nightly build=20 2000/10/31) in standalone mode, and I don't succeed in changing the root = of the=20 internal 8080 web server. I declared a new context in the server.xml=20 file:
 
         <Context = path=3D"/"=20
           =20 docBase=3D"c:/Program Files/Calendra/cdm20/server-root"=20
            = debug=3D"0"=20
     reloadable=3D"true" >=20
          =20 <RequestInterceptor=20
           &nb= sp; =20 className=3D"org.apache.tomcat.request.SimpleRealm"=20
           &nb= sp; =20 filename=3D"conf/example-users.xml"
     &nbs= p;       =20 debug=3D"0"=20 />
          &nbs= p;=20 <Logger name=3D"cdm_log"=20
           &nb= sp; =20 path=3D"logs/cdm.log"
        =      =20 verbosityLevel =3D "INFORMATION"=20
           &nb= sp;=20 />
          &nbs= p;=20 <ServletLogger name=3D"cdm_servlet_log"=20
           &nb= sp; =20 path=3D"logs/servlet_cdm.log"
      &nbs= p;      =20 verbosityLevel =3D "INFORMATION"=20
           &nb= sp;=20 />
       =20 </Context>
But I still have the default = Tomcat Home=20 Page when I ask for http://localhost:8080
Is it the right way to do this? = Is it=20 possible (!)? Is there another file to configure?
 
Thanks
 
P.S: this used to work with a = previous=20 version (3.2beta6)
 
Alain Origlia
 
CALENDRA
135, rue du = Dirigeable
ZI=20 Les Paluds
13783 AUBAGNE Cedex
Tel: +33 (0)4 42 18 69 90
http://www.calendra.com
=
 
 
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