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From dusenberr...@gmail.com
Subject Built-in functions and UDFs
Date Fri, 30 Jun 2017 19:18:40 GMT
Hi all,

Currently, the usage of UDFs is restricted to simply being able to call the UDF and assign
the results to a variable.  If the user wishes to use the UDF as input to a built-in op of
any sort on the same line, an error is thrown.  This is confusing for users, and leads to
messy code involving temporary variables.

Here is a simple example that does not work, yet should:

    out = my_udf_func(x) + 4


Can we please fix this?  UDFs should be treated like any other op.

Thanks,

- Mike

--

Mike Dusenberry
GitHub: github.com/dusenberrymw
LinkedIn: linkedin.com/in/mikedusenberry

Sent from my iPhone.


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