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Date: Thu, 7 Jan 2016 16:43:39 +0000 (UTC)
From: "Hans Fischer (JIRA)" <jira@apache.org>
To: issues@spark.apache.org
Message-ID: <JIRA.12906260.1445353157000.45445.1452185019891@Atlassian.JIRA>
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 <JIRA.12906260.1445353157459@arcas>
Subject: [jira] [Reopened] (SPARK-11214) Join with Unicode-String results
 wrong empty
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     [ https://issues.apache.org/jira/browse/SPARK-11214?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Hans Fischer reopened SPARK-11214:
----------------------------------

Guys, I have a reason for the joining Problem.
Use this code in pyspark:

from pyspark import SparkContext, SparkConf
from pyspark.sql import HiveContext

conf = (SparkConf() 
        .setAppName("joining_test")
        
        .setMaster("yarn-client")
        
        .set("spark.driver.cores", "20")
        .set("spark.driver.memory", "50g")
        .set("spark.driver.maxResultSize", "0")
        
        .set("spark.num.executors", "5")
        .set("spark.executor.cores", "10")
#        .set("spark.executor.memory", "40G")
        )

sc = SparkContext(conf=conf)
hiveContext = HiveContext(sc)

hiveContext.sql('SELECT * FROM (SELECT "a" AS a) AS a JOIN (SELECT "a" AS b) AS b ON a.a = b.b').take(10)

When ".set("spark.executor.memory", "40G")" is commented out the result will be right.
When the executor momory is set the result will be empty.

Could somebody validate this?

Thank you

> Join with Unicode-String results wrong empty
> --------------------------------------------
>
>                 Key: SPARK-11214
>                 URL: https://issues.apache.org/jira/browse/SPARK-11214
>             Project: Spark
>          Issue Type: Bug
>          Components: PySpark, SQL
>    Affects Versions: 1.5.0
>            Reporter: Hans Fischer
>            Assignee: Josh Rosen
>            Priority: Critical
>             Fix For: 1.5.1
>
>
> I created a join that should clearly result in a single row but return: empty. Could someone validate this bug?
> hiveContext.sql('SELECT * FROM (SELECT "c" AS a) AS a JOIN (SELECT "c" AS b) AS b ON a.a = b.b').take(10)
> result: []
> kind regards
> Hans


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