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From Jiri Krutil <j...@krutil.com>
Subject Re: Binding declaration in C++ messaging client
Date Mon, 04 Jul 2011 12:23:39 GMT
> > Using the C++ messaging client, I would like to declare a binding from
> > exchange E to queue Q without declaring the exchange or the queue;
> > assuming both already exist. (I want to avoid their declaration because
> > I don't know all their attributes, so in case they don't exist, I want
> > to get an error.)
> >
> > Is this perhaps possible by creating a Sender to an exchange that always
> > exists (say amq.direct) and specifying my binding between E and Q in the
> > Address (in the x-bindings list under node)?
> Yes, but the x-bindings should then appear in the link, not the node. 
> The node bindings are evaluated only if the node needs to be created. 
> The link bindings are evaluated whenever a 'link' to or from the node, 
> i.e. a sender or receiver, is created.
> E.g. Assuming an exchange my-exchange and queue my-queue (which were 
> separately configured or pre-exist), I can create a sender to:
>    my-exchange/my-key; {link:{x-bindings:[{exchange:my-exchange, 
> queue:my-queue, key:my-key}]}}
> which on creation will result in the binding being created. Note however 
> that the binding will be destroyed when the sender is closed.

I simply need to bind a queue to an exchange and I need the binding to
stay there even if I disconnect. I don't want to declare the queue or
the exchange or send or receive any messages.

Can I do this using the C++ messaging client?

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