Hi. The problem is not with fractions but with the values you expect in your conditional. Your formula only applies when A23 < B9 or when A23 = (1,2,3,4,5,6,7,8). You can fix in your last IF: ...IF(A23=8;\$F\$16;1 )... or maybe you're looking for something like : =IF(A23<\$B\$9;\$F\$8;IF(A23>8;\$F\$16;IF(A23>7;\$F\$15;IF(A23>6;\$F\$14;IF(A23>5;\$F\$13;IF(A23>4;\$F\$12;IF(A23>3;\$F\$11;IF(A23>2;\$F\$10;IF(A23>1;\$F\$9;1)))))))))*A23*D23 ----- Mensaje original ----- De: "Явор Маринов" Para: users@openoffice.apache.org Enviados: Lunes, 3 de Junio 2013 11:18:35 Asunto: Problem with a formula Hello, I'm having a problem with a formula that i have =IF(A23<\$B\$9;\$F\$8;IF(A23=1;\$F\$9;IF(A23=2;\$F\$10;IF(A23=3;\$F\$11;IF(A23=4;\$F\$12;IF(A23=5;\$F\$13;IF(A23=6;\$F\$14;IF(A23=7;\$F\$15;IF(A23=8;\$F\$16)))))))))*A23*D23 If the content of A23 is integer the formula works fine, but if the content of A23 is а fraction the result is 0. Can anyone point where can be the mistake? --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscribe@openoffice.apache.org For additional commands, e-mail: users-help@openoffice.apache.org -- Luis Iglesias Rejas Servizo de Administración Electrónica Praza do Rei, 1 - Planta 7ª 36202 VIGO Tfno: 986 810 159 / Fax: 986 220 341 Web: www.vigo.org