= The problem is not with fractions but with the values you expect in your co= nditional. Your formula only applies when A23 < B9 or when A23 =3D (1,2,= 3,4,5,6,7,8). You can fix in your last IF:
...IF(A23=3D8;\$F\$16;1)...
= or maybe you're looking for something like:
=3DIF(A23<\$B\$9;\$F\$8;IF(A2= 3>8;\$F\$16;IF(A23>7;\$F\$15;IF(A23>6;\$F\$14;IF(A23>5;\$F\$13;IF(A23&g= t;4;\$F\$12;IF(A23>3;\$F\$11;IF(A23>2;\$F\$10;IF(A23>1;\$F\$9;1)))))))))*A= 23*D23

De: "=D0=AF=D0=B2=D0=BE=D1=80 =D0= =9C=D0=B0=D1=80=D0=B8=D0=BD=D0=BE=D0=B2" <ymarinov@neterra.net>
Para: users@openoffice.apache.org
Enviados: Lunes, 3 de Juni= o 2013 11:18:35
Asunto: Problem with a formula

Hello,
<= br>I'm having a problem with a formula that i have

=3DIF(A23<\$B\$9= ;\$F\$8;IF(A23=3D1;\$F\$9;IF(A23=3D2;\$F\$10;IF(A23=3D3;\$F\$11;IF(A23=3D4;\$F\$12;IF= (A23=3D5;\$F\$13;IF(A23=3D6;\$F\$14;IF(A23=3D7;\$F\$15;IF(A23=3D8;\$F\$16)))))))))*= A23*D23

If the content of A23 is integer the formula works fine, but= if the
content of A23 is =D0=B0 fraction the result is 0.

Can a= nyone point where can be the mistake?

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= <= span style=3D"color: rgb(115, 115, 115);">Luis Iglesias Re= jas