Yes, it was stated as 1 to N. But it happens that 0 to N has the same result and the formula works either way.
- Dennis
(The usual proof is a little different, so instead of N terms all of which total N+1, the numerator represents N+1 terms all of which total N.)
-----Original Message-----
From: Dale Erwin [mailto:dale@casaerwin.org]
Sent: Friday, June 21, 2013 02:01 PM
To: users@openoffice.apache.org
Subject: Re: Calc: Easy way to do N+(N-1)+(N-2)+(N-3)..(N-N+1)
I don't think that n can be zero.
Dale Erwin
Jr. 28 de Julio 657, Depto. 03
Magdalena del Mar, Lima 17 PERU
http://leather.casaerwin.org
On 6/21/2013 1:37 PM, Brian Barker wrote:
> At 18:27 21/06/2013 +0000, Jonathon 'Toki' Kantoor wrote:
>> Is there a formula, extension, or something in calc that enables one
>> to calculate the sum of 1..N, where N is an integer between 0 and 100
>> 000 000?
>
> Yes. Sigma (1 to n) is n(n+1)/2.
>
>> If so, what is the formula, extension, or something?
>
> =Xn*(Xn+1)/2
>
> I trust this helps.
>
> Brian Barker
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