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From "Fay Wang (JIRA)" <j...@apache.org>
Subject [jira] Commented: (OPENJPA-1819) ORDER BY will append additional column to the SELECT clause which may potentialy cause ORA-00979 error
Date Thu, 30 Sep 2010 16:03:38 GMT

    [ https://issues.apache.org/jira/browse/OPENJPA-1819?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=12916529#action_12916529
] 

Fay Wang commented on OPENJPA-1819:
-----------------------------------

This apparently is not specific to Oracle. When running against DB2, the generated SQL is:

SELECT t1.id, t1.name, SUM(t0.score) AS r3, t0.person 
FROM Exam t0 
LEFT OUTER JOIN Person t1 ON t0.PERSON_ID = t1.id 
GROUP BY t1.id, t1.name ORDER BY t0.person ASC 

and DB2 throws the following exception:
com.ibm.db2.jcc.am.ro: DB2 SQL Error: SQLCODE=-119, SQLSTATE=42803, SQLERRMC=person, DRIVER=3.58.82

> ORDER BY will append additional column to the SELECT clause which may potentialy cause
ORA-00979 error
> ------------------------------------------------------------------------------------------------------
>
>                 Key: OPENJPA-1819
>                 URL: https://issues.apache.org/jira/browse/OPENJPA-1819
>             Project: OpenJPA
>          Issue Type: Bug
>          Components: sql
>    Affects Versions: 2.1.0
>         Environment: OpenJPA 2.1
> Oracle 9.2
>            Reporter: Azuo Lee
>            Priority: Critical
>
> Assuming entity Person and entity Exam has one-to-many association, the following JPQL
statement:
> SELECT p.id r1, p.name r2, sum(e.score) r3 FROM Exam e LEFT JOIN e.person p GROUP BY
p.id, p.name ORDER BY p.id
> will produce the following SQL, which is not executable if the underlining database is
Oracle 9.2:
> SELECT t1.id, t1.name, SUM(t0.score) AS r3, t0.person FROM exams t0, persons t1 WHERE
t0.person = t1.id(+) GROUP BY t1.id, t1.name ORDER BY t0.person ASC
> The additional column "t0.person" will cause error ORA-00979: not a GROUP BY expression.
> The correct SQL should be:
> SELECT t1.id, t1.name, SUM(t0.score) AS r3 FROM exams t0, persons t1 WHERE t0.person
= t1.id(+) GROUP BY t1.id, t1.name ORDER BY t1.id ASC

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