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From "Kevin Sutter (JIRA)" <>
Subject [jira] Commented: (OPENJPA-312) derby fails with duplicate primary key(s) in group by list
Date Mon, 13 Aug 2007 16:21:31 GMT


Kevin Sutter commented on OPENJPA-312:

The code is much cleaner now.  Thanks.  But, I don't think the performance of StringTokenizer
is worth any advantages it might provide.  Is there some reason why the previous mechanism
of just using indexOf() wasn't sufficient?  I like the idea of isolating this check to a single
boolean method like you have, but I would like to see a better performing implementation.


> derby fails with duplicate primary key(s) in group by list
> ----------------------------------------------------------
>                 Key: OPENJPA-312
>                 URL:
>             Project: OpenJPA
>          Issue Type: Bug
>          Components: sql
>    Affects Versions: 1.0.0
>            Reporter: Daniel Lee
>            Assignee: Daniel Lee
>            Priority: Minor
>             Fix For: 1.0.0
>         Attachments: OPENJPA-312.patch, OPENJPA-312.patch
> derby fails with duplicate primary key(s) in group by list
> With query "select o.customer, avg(o.amount) from Order o group by o.customer" the push-down
query contains duplicate columns in the group by clause.  This is okay when DB2 and other
DB that tolerate the duplicates but Derby returns error.
> Of course, we can ask fix on Derby but we can also easy fix in OpenJPA to avoid duplicates
in the group by list.  Please refer to the following for the error result and the attach patch
for the fix.
> Output from running the query that generate duplicate in the group by list:
> 6429  demo  TRACE  [main] openjpa.Query - Executing query: select o.customer, avg(o.amount)
from Order o group by o.customer
> 6639  demo  TRACE  [main] openjpa.jdbc.SQL - <t 1094861122, conn 1639735740> executing
prepstmnt 1405375428 SELECT t1.countryCode,, t1.version,, t1.state, t1.street,, t1.creditRating,, AVG(t0.amount) FROM Order t0 INNER JOIN Customer t1 ON t0.customer_countryCode
= t1.countryCode AND t0.customer_id = GROUP BY t1.countryCode,, t1.version, t1.countryCode,,, t1.state, t1.street,, t1.countryCode,, t1.creditRating,

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