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From Ted Dunning <ted.dunn...@gmail.com>
Subject Re: Why is Lanczos deprecated?
Date Sat, 03 Aug 2013 21:16:47 GMT
On Sat, Aug 3, 2013 at 3:05 AM, Fernando Fernández <
fernando.fernandez.gonzalez@gmail.com> wrote:

> > svd.r$d[1:10] [1] 640.63362 244.83635 217.84622 159.15360 158.21191
> 145.87261 126.57977 121.90770 106.82918  99.74794[1] "three runs with q=0"
> [1] 640.63362 244.83613 217.84493 159.14512 158.20471 145.82572 126.42295
> 121.79764 105.99973  98.99649 [1] 640.63362 244.83592 217.84568 159.13914
> 158.19299 145.84226 126.46651 121.73629 106.22892  99.11622 [1] 640.63362
> 244.83590 217.84482 159.12955 158.19675 145.81728 126.47135 121.79920
> 106.45790  99.01242
>
> [1] "three runs with q=1" [1] 640.63259 244.75889 217.66362 158.40002
> 157.61954 145.26448 125.25675 119.74266 104.16382  95.43547 [1]
> 640.6327 244.7559 217.6805 158.6019 157.4059 144.9223 124.2859
> 119.1194 103.9104  96.6282 [1] 640.63313 244.62599 217.67781 158.72475
> 157.13394 145.08462 125.33024 120.20984 102.45867  95.37994
>
>
> I have repeated the runs several times with the same results... Maybe I'm
> still missing something else but given these results I can't apply the rule
> of q=1 improves accuracy. At least I have to experiment, my guess is it do
> depends on the dataset. I would like also to repeat this comparison with
> Mahout's SSVD and my dataset and see what happens.
>
> Dmitriy, thank you very much for your attention and sharing your thoughts
> with me. I really appreciate it.
>

That is interesting.

The results for q=0 and q=1 are remarkably similar which I wouldn't expect.

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