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From PEDRO MANUEL JIMENEZ RODRIGUEZ <pmjimenez1...@hotmail.com>
Subject RE: Lanczos Algorithm
Date Mon, 22 Nov 2010 21:07:38 GMT

Hi Ted,

I can't give you an exact amount but more or less it could be around 10^5 non-zero elements
per row.

Could you please let me know, why the lanzcos algorithm is not always returning the values
in a decreasing order?

Thanks.

Pedro.

----------------------------------------
> From: ted.dunning@gmail.com
> Date: Fri, 19 Nov 2010 13:34:19 -0800
> Subject: Re: Lanczos Algorithm
> To: user@mahout.apache.org
>
> How many non-zero elements?
>
> On Fri, Nov 19, 2010 at 12:34 PM, PEDRO MANUEL JIMENEZ RODRIGUEZ <
> pmjimenez1983@hotmail.com> wrote:
>
> >
> >
> > I was talking about 10^9 rows and 10^9 columns
> >
> > ----------------------------------------
> > > From: ted.dunning@gmail.com
> > > Date: Fri, 19 Nov 2010 12:07:16 -0800
> > > Subject: Re: Lanczos Algorithm
> > > To: user@mahout.apache.org
> > >
> > > On Fri, Nov 19, 2010 at 11:17 AM, PEDRO MANUEL JIMENEZ RODRIGUEZ <
> > > pmjimenez1983@hotmail.com> wrote:
> > >
> > > > In this project I would have to work with matrix of 10^9, which have a
> > very
> > > > sparse data.
> > >
> > >
> > > I think you mean 10^9 rows and 10^9 columns with much fewer 10^18
> > non-zero
> > > elements.
> > >
> > > Is that correct?
> > >
> > > Can you say how many non-zero elements?
> >
> >
 		 	   		  
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