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From Aman Deep Singh <amandeep.coo...@gmail.com>
Subject Re: Phrase Query only forward direction
Date Tue, 13 Jun 2017 05:55:23 GMT
Thanks Eric

On Mon, Jun 12, 2017 at 10:28 PM Erick Erickson <erickerickson@gmail.com>
wrote:

> Complex phrase also has an inorder flag that I think you're looking for
> here.
>
> Best,
> Erick
>
> On Mon, Jun 12, 2017 at 7:16 AM, Erik Hatcher <erik.hatcher@gmail.com>
> wrote:
> > Understood.   If you need ordered, “sloppy” (some distance) phrases, you
> could OR in a {!complexphrase} query.
> >
> >
> https://cwiki.apache.org/confluence/display/solr/Other+Parsers#OtherParsers-ComplexPhraseQueryParser
> <
> https://cwiki.apache.org/confluence/display/solr/Other+Parsers#OtherParsers-ComplexPhraseQueryParser
> >
> >
> > Something like:
> >
> >     q=({!edismax … ps=0 v=$qq}) OR {!complexphrase df=nameSearch v=$qq}
> >
> > where &qq=12345 masitha
> >
> >         Erik
> >
> >
> >> On Jun 12, 2017, at 9:57 AM, Aman Deep Singh <amandeep.cool99@gmail.com>
> wrote:
> >>
> >> Yes Erik I can use ps=0 but, my problem is that I want phrase which have
> >> same sequence and they can be present with in some distance
> >> E.g.
> >> If I have document masitha xyz 12345
> >> I want that to be boosted since the sequence is in order .That's why I
> have
> >> use ps=5
> >> Thanks,
> >> Aman Deep Singh
> >>
> >> On 12-Jun-2017 5:44 PM, "Erik Hatcher" <erik.hatcher@gmail.com> wrote:
> >>
> >> Using ps=5 causes the phrase matching to be unordered matching.   You’ll
> >> have to set ps=0, if using edismax, to get exact order phrase matches.
> >>
> >>        Erik
> >>
> >>
> >>> On Jun 12, 2017, at 1:09 AM, Aman Deep Singh <
> amandeep.cool99@gmail.com>
> >> wrote:
> >>>
> >>> Hi,
> >>> I'm using a phrase query ,but it was applying the phrase boost to the
> >> query
> >>> where terms are in reverse order also ,which i don't want.Is their any
> way
> >>> to avoid the phrase boost for reverse order and apply boost only in
> case
> >> of
> >>> terms are in same sequence
> >>>
> >>> Solr version 6.5.1
> >>>
> >>> e.g.
> >>> http://localhost:8983/solr/l4_collection/select?debugQuery=o
> >> n&defType=edismax&fl=score,nameSearch&indent=on&mm=100%25&
> >> pf=nameSearch&q=12345%20masitha&qf=nameSearch&wt=xml&ps=5
> >>>
> >>>
> >>> while my document has value
> >>>
> >>> in the debug query it is applying boost as
> >>> 23.28365 = sum of:
> >>> 15.112219 = sum of:
> >>> 9.669338 = weight(nameSearch:12345 in 0) [SchemaSimilarity], result of:
> >>> 9.669338 = score(doc=0,freq=1.0 = termFreq=1.0
> >>> ), product of:
> >>> 7.6397386 = idf, computed as log(1 + (docCount - docFreq + 0.5) /
> (docFreq
> >>> + 0.5)) from:
> >>> 2.0 = docFreq
> >>> 5197.0 = docCount
> >>> 1.2656635 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 -
> b +
> >> b
> >>> * fieldLength / avgFieldLength)) from:
> >>> 1.0 = termFreq=1.0
> >>> 1.2 = parameter k1
> >>> 0.75 = parameter b
> >>> 5.2576485 = avgFieldLength
> >>> 2.56 = fieldLength
> >>> 5.44288 = weight(nameSearch:masitha in 0) [SchemaSimilarity], result
> of:
> >>> 5.44288 = score(doc=0,freq=1.0 = termFreq=1.0
> >>> ), product of:
> >>> 4.3004165 = idf, computed as log(1 + (docCount - docFreq + 0.5) /
> (docFreq
> >>> + 0.5)) from:
> >>> 70.0 = docFreq
> >>> 5197.0 = docCount
> >>> 1.2656635 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 -
> b +
> >> b
> >>> * fieldLength / avgFieldLength)) from:
> >>> 1.0 = termFreq=1.0
> >>> 1.2 = parameter k1
> >>> 0.75 = parameter b
> >>> 5.2576485 = avgFieldLength
> >>> 2.56 = fieldLength
> >>> 8.171431 = weight(*nameSearch:"12345 masitha"~5 *in 0)
> [SchemaSimilarity],
> >>> result of:
> >>> 8.171431 = score(doc=0,freq=0.33333334 = phraseFreq=0.33333334
> >>> ), product of:
> >>> 11.940155 = idf(), sum of:
> >>> 7.6397386 = idf, computed as log(1 + (docCount - docFreq + 0.5) /
> (docFreq
> >>> + 0.5)) from:
> >>> 2.0 = docFreq
> >>> 5197.0 = docCount
> >>> 4.3004165 = idf, computed as log(1 + (docCount - docFreq + 0.5) /
> (docFreq
> >>> + 0.5)) from:
> >>> 70.0 = docFreq
> >>> 5197.0 = docCount
> >>> 0.6843655 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 -
> b +
> >> b
> >>> * fieldLength / avgFieldLength)) from:
> >>> 0.33333334 = phraseFreq=0.33333334
> >>> 1.2 = parameter k1
> >>> 0.75 = parameter b
> >>> 5.2576485 = avgFieldLength
> >>> 2.56 = fieldLength
> >>>
> >>> Thanks,
> >>> Aman Deep Singh
> >
>

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