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From Nigel <>
Subject Re: Efficiently reopening remotely-distributed indexes in 2.9?
Date Thu, 08 Oct 2009 18:02:31 GMT
Thanks, Mark.  That makes sense.  I guess if you do it in the right order,
you're guaranteed to have the files in a consistent state, since the only
thing that's actually overwritten is the segments.gen file at the end.

What about the technique of creating a copy of the directory with hard links
and rsyncing changes into that copy?  Is that only necessary if you want to
be using the old and updated versions of the index simultaneously?


On Wed, Oct 7, 2009 at 4:02 PM, Mark Miller <> wrote:

> Solr just copies them into the same directory - Lucene files are write
> once, so its not much different than what happens locally.
> Nigel wrote:
> > Right now we logically re-open an index by making an updated copy of the
> > index in a new directory (using rsync etc.), opening the new copy, and
> > closing the old one.  We don't use IndexReader.reopen() because the
> updated
> > index is in a different directory (as opposed to being updated in-place).
> >
> > (Reading about some of the 2.9 changes motivated me to look into actually
> > using reopen().  And Michael Busch and Mark Miller both pointed out that
> I
> > was incorrect in saying that pre-2.9 reopen() wasn't more efficient than
> > just opening a new index -- I've read through that code now so I have at
> > least a basic understanding of what's happening there.  Anyway, it seems
> > like reopen() is a Good Thing, so I'd like to use it. (-:)
> >
> > So, my real question was whether there is a "recommended" way to update
> an
> > index in-place with files copied from a separate indexing server.
> >
> > For example, do you simply rsync in the new cfs files, overwrite the
> > segments.gen and segments_XX files, and call reopen()?  Or create an
> updated
> > copy in a new directory, then rename new directory to the old name once
> > you're sure you've copied everything successfully, then call reopen()?
>  What
> > does Solr do?
> >
> > Thanks,
> > Chris

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