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From jason <ginger...@gmail.com>
Subject Re: understand the queryNorm and the fieldNorm.
Date Mon, 06 Feb 2006 17:50:38 GMT
hi, thx.

I think i forget the ^0.5

cheers
Jason


On 2/6/06, Yonik Seeley <yseeley@gmail.com> wrote:
>
> Hi Jason,
> I get the same thing for the queryNorm when I calculate it by hand:
> 1/((1.7613963**2 + 1.326625**2)**.5)  = 0.45349488111693986
>
> -Yonik
>
> On 2/6/06, jason <gingerons@gmail.com> wrote:
> > Hi,
> >
> > I have a problem of understanding the queryNorm and fieldNorm.
> >
> > The following is an example. I try to follow what said in the Javadoc
> > "Computes the normalization value for a query given the sum of the
> squared
> > weights of each of the query terms". But the result is different.
> >
> > ID:0 C:/PDF2Text/SearchEngine/File/SIG/sigkdd/p374-zhang.pdf|initialrank: 0
> > 0.31900567 = sum of:
> >   0.03968133 = weight(contents:associ in 920), product of:
> >     0.60161763 = queryWeight(contents:associ), product of:
> >       1.326625 = idf(docFreq=830)
> >       0.45349488 = queryNorm
> >     0.065957725 = fieldWeight(contents:associ in 920), product of:
> >       4.2426405 = tf(termFreq(contents:associ)=18)
> >       1.326625 = idf(docFreq=830)
> >       0.01171875 = fieldNorm(field=contents, doc=920)
> >   0.27932435 = weight(contents:rule in 920), product of:
> >     0.7987842 = queryWeight(contents:rule), product of:
> >       1.7613963 = idf(docFreq=537)
> >       0.45349488 = queryNorm
> >     0.34968686 = fieldWeight(contents:rule in 920), product of:
> >       16.941074 = tf(termFreq(contents:rule)=287)
> >       1.7613963 = idf(docFreq=537)
> >       0.01171875 = fieldNorm(field=contents, doc=920)
> >
> > regards
> > jiang xing
> >
> >
>
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