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From "Ryan McKinley (JIRA)" <j...@apache.org>
Subject [jira] Commented: (SOLR-2366) Facet Range Gaps
Date Thu, 17 Feb 2011 15:01:26 GMT

    [ https://issues.apache.org/jira/browse/SOLR-2366?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=12995838#comment-12995838
] 

Ryan McKinley commented on SOLR-2366:
-------------------------------------

I agree with grant that this syntax is more clear then using facet.query for each bucket.

Just throwing it out there... but is there a way to not specify the start/end, and have that
based on the values in the index?  start=* end=*?  In this case, it would be nice to specify
the gap as round numbers.  Perhaps gap=%10?  assuming you have the values: 22,28,35, that
would give you gaps for 20-30 and 30-40

> Facet Range Gaps
> ----------------
>
>                 Key: SOLR-2366
>                 URL: https://issues.apache.org/jira/browse/SOLR-2366
>             Project: Solr
>          Issue Type: Improvement
>            Reporter: Grant Ingersoll
>            Priority: Minor
>             Fix For: 3.2, 4.0
>
>         Attachments: SOLR-2366.patch, SOLR-2366.patch
>
>
> There really is no reason why the range gap for date and numeric faceting needs to be
evenly spaced.  For instance, if and when SOLR-1581 is completed and one were doing spatial
distance calculations, one could facet by function into 3 different sized buckets: walking
distance (0-5KM), driving distance (5KM-150KM) and everything else (150KM+), for instance.
 We should be able to quantize the results into arbitrarily sized buckets.  I'd propose the
syntax to be a comma separated list of sizes for each bucket.  If only one value is specified,
then it behaves as it currently does.  Otherwise, it creates the different size buckets. 
If the number of buckets doesn't evenly divide up the space, then the size of the last bucket
specified is used to fill out the remaining space (not sure on this)
> For instance,
> facet.range.start=0
> facet.range.end=400
> facet.range.gap=5,25,50,100
> would yield buckets of:
> 0-5,5-30,30-80,80-180,180-280,280-380,380-400

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