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Date: Mon, 31 Aug 2009 05:50:30 -0700 (PDT)
From: utuncdemir <camoka@gmail.com>
To: java-dev@lucene.apache.org
Subject: Re: ParseException
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 <55e2bf7e0908280906h60655ef7w89c3a1996ca0fcc7@mail.gmail.com>


Thank you for reply but it works in case only Analyzer is SimpleAnalyzer.It
doesnt throw exception but also can not find results too in case the
analyzer is either KeywordAnalyzer or StandartAnalyzer..do you have a clue
that what can be cause of this ? Is it bug maybe or is it the implementation
of these analyzers so it is working as how it should ?


Adriano Crestani-2 wrote:
> 
> Hi,
> 
> You can escape the query parser keywords: Holland \OR Germany
> 
> This way the query parser will interpret it as as term instead of a
> boolean
> operator.
> 
> Regards,
> Adriano Crestani
> 
> On Fri, Aug 28, 2009 at 3:51 AM, utuncdemir <camoka@gmail.com> wrote:
> 
>>
>> Hello
>>
>> When search term has word 'OR', Lucene throws an ParseException but here
>> the
>> term 'OR' is not searched for to be interpreted by condition in query
>> intentionally.The needs is simple to get the lucene document which has
>> text
>> for example ' Holland OR Germany '.in other words when i search for
>> 'Holland
>> OR Germany' for example, i dont want the lucene documents which contains
>> either text 'Holland' or 'Germany'.I want simply the document which has
>> exactly containing the text ' Holland OR Germany '.I want the 'OR' term
>> interpreted as usual string not search operator in Lucene.
>>
>> When i try same with Luke, also i am having same problem there.
>>
>> How can i avoid this and make Lucene interpret search operators in its
>> own
>> implementation as simple text ?
>>
>> Thank you in advance.
>> --
>> View this message in context:
>> http://www.nabble.com/ParseException-tp25185575p25185575.html
>> Sent from the Lucene - Java Developer mailing list archive at Nabble.com.
>>
>>
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>>
> 
> 

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