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From "Jason Kania (JIRA)" <j...@apache.org>
Subject [jira] [Created] (KAFKA-2634) KafkaProducer hangs on future.get()
Date Mon, 12 Oct 2015 18:10:05 GMT
Jason Kania created KAFKA-2634:

             Summary: KafkaProducer hangs on future.get()
                 Key: KAFKA-2634
                 URL: https://issues.apache.org/jira/browse/KAFKA-2634
             Project: Kafka
          Issue Type: Bug
    Affects Versions:,
         Environment: Windows 8 PC connecting to local ubuntu VM running kafka in docker image
with topic set up having 1 partition and a replication factor of 1
            Reporter: Jason Kania
            Priority: Blocker

When running the Kafka Producer at the end of this description, the following problems occur:

1) If the ip address of the server running the kafka queue is incorrect or unavailable, the
producer times out without ever indicating that the node could not be found. The time out
exception should indicate if the node could not be connected to in the first place or if communication
timed out during communication with the node.

2) In my situation, the client connects to the kafka queue according to server logs, but never
returns from the get() call on the producer side. This get call too should time out indicating
what the producer was waiting on when it timed out. At present there are no details to indicate
how to debug.

The issue is a blocker in my view because there are no error details that allow debugging
of the issue even when the log4j properties of the server are set as detailed as possible.

public class BrokenProducer
	public static void main(String[] args)
		Properties properties = new Properties();
		properties.put("bootstrap.servers", "<VM IP address>:9092");
		properties.put("key.serializer", "org.apache.kafka.common.serialization.StringSerializer");
		properties.put("value.serializer", "org.apache.kafka.common.serialization.StringSerializer");
		KafkaProducer producer = new KafkaProducer<String,String>( properties );
			producer.send(new ProducerRecord("myQueue", "aString")).get();
		catch (Exception e)

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