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From harry_no_spot <13651877...@163.com>
Subject Re:Re:how to evaluate function set in variable?
Date Mon, 15 Aug 2016 14:48:05 GMT
Still not understand why
println ${__eval(vars.get("var"))}
will print

${__time(yyyyMMdd)}
instead of
20160815



At 2016-08-15 22:32:11, "harry_no_spot" <13651877684@163.com> wrote:
>I answer myself.
>use println  ${__eval(${var})}  will be ok
>use println ${__eval(vars.get("var"))} will be not ok.
>
>
>At 2016-08-11 21:32:01, "harry_no_spot" <13651877684@163.com> wrote:
>>hi, plz help me, the question is:
>>1. senario as expected:
>>a.create a csv file, contents is
>>var
>>123
>>b.very simple test plan. 'CSV data set config' & 'JSR223 Sampler'
>>c. println ${__eval(vars.get("var"))}  
>>it prints 123 on console as expected.
>>
>>2. senario not as expected
>>a. change csv file, content is
>>var
>>${__time(yyyyMMdd)}
>>b. it prints ${__time(yyyyMMdd)} on console, not as expected, say, 20160811
>>
>>so why?
>>
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