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From Benson Margulies <bimargul...@gmail.com>
Subject Re: sparql versus ^^ types
Date Fri, 10 Dec 2010 19:09:57 GMT
I'm having trouble putting my hands on createPlainLiteral. I see it in
ResourceFactory, but not model. Do I just call it from there.

On Fri, Dec 10, 2010 at 1:38 PM, Ian Dickinson <ian@epimorphics.com> wrote:
> Hi Benson,
>
> On 10/12/10 18:18, Benson Margulies wrote:
>>
>> To be clearer, the resulting OWL RDF has
>> rdf:datatype="http://www.w3.org/2001/XMLSchema#string"
>>  attributes, and then tdbdump shows ^^ suffixes.
>>
>> On Fri, Dec 10, 2010 at 12:20 PM, Benson Margulies
>> <bimargulies@gmail.com>  wrote:
>>>
>>> Andy,
>>>
>>> I'm having trouble getting rid of all my ^^ noise.
>>>
>>> I run Jena schemagen against an Ontology that has no type annotations,
>>> I don't see any in the output of schemagen, but calls to
>>>
>>>  entityRef = model.createIndividual(entityUri, oclass);
>>>            entityRef.addLiteral(Rex.hasEntityDetectionSource, source);
>>>            entityRef.addLiteral(Rex.hasNormalizedText, normalizedText);
>>>            entityRef.addLiteral(Rex.hasOriginalText, rawText);
>>>
>>> end up adding the ^^ and the string data type.
>
> If you look at the Javadoc for Resource.addLiteral, there's no overloaded
> type signature for addLiteral( Property, String ). Which means that you're
> actually invoking this method:
>
> http://openjena.org/javadoc/com/hp/hpl/jena/rdf/model/Resource.html#addLiteral(com.hp.hpl.jena.rdf.model.Property,%20java.lang.Object)
>
> which says:
>
> """
> Add the property p with the typed-literal value o to this resource, ie add
> (this, p, typed(o)) to this's model. Answer this resource. The typed literal
> is equal to one constructed by using this.getModel().createTypedLiteral(o).
> """
>
> You want either:
>
> entityRef.addProperty(Rex.hasEntityDetectionSource, source);
>
> or
>
> entityRef.addLiteral(Rex.hasEntityDetectionSource, model.createPlainLiteral(
> source ));
>
> Ian
>

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