I tried escaping @ as \@ but the parser fussed about having a \ in that
position.  Am I escaping it incorrectly?

As a test, I tried replacing @ with %40 and the parser didn't like %.


On Mon, Sep 13, 2010 at 7:47 PM, Ian Boston <ieb@tfd.co.uk> wrote:

> Have you tried escaping the @
> IIRC there is a JCRUtils method for the purpose.
> Ian
>
> On 14 Sep 2010, at 06:55, Carl Hall wrote:
>
> > I'm using the following XPath and can't get around having an @ symbol in
> a
> > node name (name == "test@example.com").  Is there a way for me to escape
> > this so I can query?
> >
> > //element(*, sakai:pooled-content)[(jcr:contains(., '*') or
> > jcr:contains(jcr:content, '*')) and (t/te/
> > test@example.com/@sakai:pooled-content-manager='test@example.com') ]
> order
> > by @jcr:created descending
> >
> >
> > Before we started allowing @ in the username, the query worked fine but
> > fails now with: "Encountered: "@" (64), after : ""
> > at
> >
> org.apache.jackrabbit.spi.commons.query.xpath.XPathTokenManager.getNextToken(XPathTokenManager.java:13261)"
> >
> > Thanks,
> > Carl
>
>