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From "Stefan Guggisberg" <stefan.guggisb...@gmail.com>
Subject Re: Getting the size of binary node content
Date Thu, 04 Oct 2007 12:14:19 GMT
On 10/4/07, Paco Avila <pavila@git.es> wrote:
> El mié, 03-10-2007 a las 14:02 +0200, Stefan Guggisberg escribió:
> > On 10/2/07, Paco Avila <pavila@git.es> wrote:
> > > El mar, 02-10-2007 a las 15:07 +0200, Thomas Mueller escribió:
> > > > Hi,
> > > >
> > > > Property.getLength():
> > > > Returns the length of the value of this property. Returns the length
> > > > in bytes if the value is a PropertyType.BINARY, otherwise it returns
> > > > the number of characters needed to display the value in its string
> > > > form. Returns -1 if the implementation cannot determine the length.
> > > >
> > > > Does this not work, or did I misunderstand the problem?
> > >
> > > I didn't notice the method :) Anyway, "Property.getLength()" is supposed
> > > to be so fast as getting the size stored in special a property?
> >
> > yes, in fact even faster ;)
>
> Do you mean that "node.getProperty("jcr:data").getLength()" is faster
> than "node.getProperty("my:size")?

no. i was saying that

    property.getLenght();

is probably faster than

   node.getProperty("my:size").getLong();

i.e. i was assuming that you'd already read the property.
if that's not the case just reading a LONG property
is certainly faster that reading a BINARY property.
>
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