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From Peeter Piegaze <peeter.pieg...@gmail.com>
Subject Re: sibling and basic understanding of jsr 170
Date Mon, 13 Dec 2004 17:31:04 GMT
Hi Markus,

Just wanted to point out also that this info hasn't got anything to do
with NodeType, this is on the Node instance. So, as Stefan suggests,
the relevant method is Item.getPath (Item being a supclass of Node).

Cheers,
Peeter


On Mon, 13 Dec 2004 18:27:10 +0100, Stefan Guggisberg
<stefan.guggisberg@gmail.com> wrote:
> hi markus,
> you're right, there's no easy solution for your particular use case,
> 
> you could write a short utility method though, something like
> 
> Node getSiblingOf(Node n, int index)
> 
> that method would
> 
> 1. extract the current subscript from the path of n (n.getPath()),
>    e.g. 99
> 2. compute new subscript (99-1=98)
> 3. get sibling with
>    n.getParent().getNode(n.getName() + "[" + subscript + "]")
> 
> not very elegant but more efficient than iterating over all children...
> 
> cheers
> stefan
> 
> 
> 
> 
> On Mon, 13 Dec 2004 18:04:46 +0100, jocsch <jocsch@freaquac.de> wrote:
> > Hi,
> >
> > sorry for posting a more jcr related question than a jackrabbit one, but I'm
> > not in the expert group ;-)
> >
> > I have a problem finding a sibling related to a given Node.
> > I set up a container node which has an undetermined number of children. The
> > order of the children matters. So it looks like:
> >
> > RN
> >  |
> >  tst:container
> >     |-...
> >     |-tst:child[98]
> >     |-tst:child[99]
> >     |-....
> >
> > Now I have a use case where tst:child[99] is given and I need to show its
> > preceding sibling tst:child[98].
> > I found no possibility to get this node other than iterating over all children
> > (comparing to the given node and remembering the preceding node), because it
> > seems that there is no getPosition() or something like that on the Node type.
> >
> > I think this solution is far from optimal. Is there a better solution?
> > OK, I guess I can implement a kind of a linked list functionality into the
> > child node types, but if possible, I want to avoid this.
> > I know that there are xpath functions like following-sibling but I read
> > somewhere that xpath queries are not yet implemented in jackrabbit.
> >
> > Thanks,
> >  Markus
> >
>

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