Return-Path: X-Original-To: apmail-incubator-ooo-users-archive@minotaur.apache.org Delivered-To: apmail-incubator-ooo-users-archive@minotaur.apache.org Received: from mail.apache.org (hermes.apache.org [140.211.11.3]) by minotaur.apache.org (Postfix) with SMTP id 0834AC75F for ; Sun, 3 Jun 2012 17:27:14 +0000 (UTC) Received: (qmail 42645 invoked by uid 500); 3 Jun 2012 17:27:13 -0000 Delivered-To: apmail-incubator-ooo-users-archive@incubator.apache.org Received: (qmail 42604 invoked by uid 500); 3 Jun 2012 17:27:13 -0000 Mailing-List: contact ooo-users-help@incubator.apache.org; run by ezmlm Precedence: bulk List-Help: List-Unsubscribe: List-Post: List-Id: Reply-To: ooo-users@incubator.apache.org Delivered-To: mailing list ooo-users@incubator.apache.org Received: (qmail 42591 invoked by uid 99); 3 Jun 2012 17:27:13 -0000 Received: from athena.apache.org (HELO athena.apache.org) (140.211.11.136) by apache.org (qpsmtpd/0.29) with ESMTP; Sun, 03 Jun 2012 17:27:13 +0000 X-ASF-Spam-Status: No, hits=1.5 required=5.0 tests=HTML_MESSAGE,RCVD_IN_DNSWL_LOW,SPF_PASS X-Spam-Check-By: apache.org Received-SPF: pass (athena.apache.org: domain of mhenriday@gmail.com designates 74.125.82.175 as permitted sender) Received: from [74.125.82.175] (HELO mail-we0-f175.google.com) (74.125.82.175) by apache.org (qpsmtpd/0.29) with ESMTP; Sun, 03 Jun 2012 17:27:09 +0000 Received: by werg55 with SMTP id g55so2408127wer.6 for ; Sun, 03 Jun 2012 10:26:48 -0700 (PDT) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:from:date:message-id:subject:to :content-type; bh=wPyaYygCOqb0MgdkcNW23FSu0NSk+HHPK78YK95I1zQ=; b=KtPxrRAaS79EsKpH/QqkCaJPr/VLqZCKekPlAvzWfdIrp3izrOtwNe1y66fvs9ylcs VqD0cV9I8Oo/jb1Bumbmw3/Wfq/aJq7/AyrrdvpnvSOiWcZtC+cW1PKBD7URAx5huAdh t2KlUqFSy8R5+yPLxOVE7CfNh0E9nmug0xQdlUVUZLGSWd79vq4fSQmoFBZCivh1Hto2 JHwr1f0689HVYQKVj7PV0YzkOl5LSddswjxNgth2uYhV1Md0lQ/JeoyaW6FZ91C7idB/ apn3YA7exsDqVob8e+tYE86hhIpPg8goEMorkTkNdd0W4hBYXxs6gMDFmkIAO5RtWAN5 Zwxw== Received: by 10.216.136.155 with SMTP id w27mr7872682wei.43.1338744407942; Sun, 03 Jun 2012 10:26:47 -0700 (PDT) MIME-Version: 1.0 Received: by 10.180.83.68 with HTTP; Sun, 3 Jun 2012 10:26:06 -0700 (PDT) In-Reply-To: References: <4FC9BB95.1000308@scottsonline.org.uk> <4FCA6163.25862.2C7E1F8@niall.rndmartin.cix.co.uk> From: M Henri Day Date: Sun, 3 Jun 2012 19:26:06 +0200 Message-ID: Subject: Re: [Calc] Feature request: Change default cell width from 2,27cm to 2,50cm To: ooo-users@incubator.apache.org Content-Type: multipart/alternative; boundary=0016e6d99c23e1674604c194b844 X-Virus-Checked: Checked by ClamAV on apache.org --0016e6d99c23e1674604c194b844 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: quoted-printable 2012/6/3 NoOp > On 06/02/2012 11:54 AM, Niall Martin wrote: > > 2.54 cm to the inch, it certainly is by law. It follows from > > legislation in the 80s, I think, which defined the UK yard as 0.9144 > > metres exactly. If you do your arithmetic that leads to 2.54 cm to > > the inch, exactly. > > Well not *exactly* - it depends upon how many decimal places you'd care > to use, which country (most do abide by SI Units - BIPM, NIST ect), and > which law & which reference. > > > > 1 ft =3D (1200/3937) m > > 1200/3937 =3D 0.3048006096 > > =3D(1200/3937)/12 > =3D 0.0254000508 > > And of course there is the infamous '0.02540005'... > > For legal and practical purposes, in most cases, 1 inch =3D 2.54 > centimeters. And yes, I've already responded to Mike regarding this. > However, please keep in mind that your response is country centric, and > most likely refers to: > > But that "legislation" is (again) country specific and goes back to my > original comments: > You see the problem? You call it tamatoe, I call it tomato... > > [OT] Btw I pronounce 'River Thames' as th-ames (same as James) insead of > 'tems/t=C4=95mz/temmz'. I suppose there are several explainations for thi= s > (none in law that I know of), but I quite like this one: > > Any yes, all of this has been discussed/debated/departed on the old OOo > lists. So my recommendation is to let it be. > :-) > If I've calculated aright, one *inch* in the Imperial system should be approximately 1.5715917903674 x 10^33 *Planck lengths*. Apologies for any rounding errors.... Henri --0016e6d99c23e1674604c194b844--