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From "John R. Frank" <>
Subject Re: smallest/largest UUIDs for LexicalUUIDType
Date Fri, 07 Jun 2013 01:54:45 GMT
> I'll note that if you have the choice, you can use UUIDType rather than 
> LexicalUUIDType. UUIDType fixes that behavior and use a proper lexical 
> comparison for non-type-1 uuids (the other behavior of UUIDType is that 
> for type 1 uuid, it compares them by time first, i.e. it is equivalent 
> to TimeUUIDType for type 1 uuid).

That's super helpful, thanks!

Follow-up question:  it seems that range queries on the *second* field of 
a CompositeType(UUIDType(), UUIDType()) do not work.

What am I missing?

I thought that creating 1000 column names with the *same* UUID in the 
first field of the CompositeType and a random UUID in the second field 
would make it so I can get out four subranges of the second UUID by 
constructing four evenly spaced start/finish keys -- see below.

Instead, it appears that all of the rows end up in the last subrange. 
See assert below marked "this fails"

Advice on this much appreciated -- jrf

     sm = SystemManager(chosen_server)
     sm.create_keyspace(namespace, SIMPLE_STRATEGY, {'replication_factor': '1'})

     family = 'test'
         namespace, family, super=False,
         key_validation_class = ASCII_TYPE,
         default_validation_class = BYTES_TYPE,
         comparator_type=CompositeType(UUIDType(), UUIDType()),
     pool = ConnectionPool(namespace, config['storage_addresses'],
                           max_retries=1000, pool_timeout=10, pool_size=2,

     cf = pycassa.ColumnFamily(pool, family)
     u1, u2, u3, u4 = uuid.uuid1(), uuid.uuid1(), uuid.uuid1(), uuid.uuid1()

     cf.insert('inbound', {(u1, u2): b''})
     cf.insert('inbound', {(u1, u3): b''})
     cf.insert('inbound', {(u1, u4): b''})

     ## test range searching
     start  = uuid.UUID( - 1)
     finish = uuid.UUID( + 1)
     assert < <
     rec3 = cf.get('inbound',
                   column_start =(u1, start),
                   column_finish=(u1, finish)).items()
     assert len(rec3) == 1
     assert rec3[0][0][1] == u3
     ####  This assert above passes!

     ####  This next part fails :-/
     ## now insert many rows -- enough that some should fall in each
     ## subrange below
     for i in xrange(1000):
         cf.insert('inbound', {(u1, uuid.uuid4()): b''})

     ## do four ranges, and expect more than zero in each
     step_size = 2**(128 - 2)

     ## go in reverse order to illustrate that they are all at the end!!!?
     for i in range(2**2, 0, -1):
         start =  uuid.UUID(int=(i-1) * step_size)
         finish = uuid.UUID(int=min(i * step_size, 2**128 - 1))
         recs = cf.get('inbound',
                       column_start =(u1, start),
                       column_finish=(u1, finish)).items()
         for key, val in recs:
             assert val == b''
             assert start < key[1] < finish              ## this fails!!

         assert len(recs) > 0
         print len(recs), ' for ', start, finish


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