I think your math is 'relatively' correct. It would seem to me you should focus on how you can reduce the amount of storage you are using per item, if at all possible, if that node count is prohibitive.

On 04/19/2012 07:12 AM, Franc Carter wrote:


One of the projects I am working on is going to need to store about 200TB of data - generally in manageable binary chunks. However, after doing some rough calculations based on rules of thumb I have seen for how much storage should be on each node I'm worried.

  200TB with RF=3 is 600TB = 600,000GB
  Which is 1000 nodes at 600GB per node

I'm hoping I've missed something as 1000 nodes is not viable for us.



Franc Carter | Systems architect | Sirca Ltd

franc.carter@sirca.org.au | www.sirca.org.au

Tel: +61 2 9236 9118

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