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From "Modeel, Subin" <subin.mod...@hp.com>
Subject invoke REST calls from python-urllib2 gives error
Date Fri, 15 Mar 2013 09:50:55 GMT
Hi
I was trying to invoke the rest call from python-urllib2 .I see that It fails with 403 error.I
feel its because there is no realm value.
I am unable to find the WWW-Authenticate: value to find the realm value.
Can you please help me with this.


Thanks

>>> import urllib2
>>> url = 'http://localhost:8080/api/v1/clusters/'
>>> password_mgr = urllib2.HTTPPasswordMgrWithDefaultRealm()
>>> handler = urllib2.HTTPBasicAuthHandler(password_mgr)
>>> password_mgr.add_password(None,'http://localhost:8080','admin', 'admin')

>>> opener.open('http://localhost:8080/api/v1/clusters/')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python2.6/urllib2.py", line 397, in open
    response = meth(req, response)
  File "/usr/lib64/python2.6/urllib2.py", line 510, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib64/python2.6/urllib2.py", line 435, in error
    return self._call_chain(*args)
  File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib64/python2.6/urllib2.py", line 518, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Full authentication is required to access this resource



I am able to use the pycurl library to get the response.


>>> import pycurl, json
>>> url = 'http://localhost:8080/api/v1/clusters/'
>>> c = pycurl.Curl()
>>> c.setopt(pycurl.URL, url)
>>> c.setopt(pycurl.USERPWD,'admin')
>>> c.setopt(pycurl.USERPWD,'admin:admin')
>>> c.perform()
{
  "href" : "http://localhost:8080/api/v1/clusters/",
  "items" : [
    {
      "href" : "http://localhost:8080/api/v1/clusters/test1",
      "Clusters" : {
        "cluster_name" : "test1",
        "version" : "HDP-1.2.0"
      }
    }
  ]
}

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