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From Christopher Schultz <ch...@christopherschultz.net>
Subject Re: [users@httpd] find IP and PORT in use by Apache
Date Tue, 21 Jun 2016 18:58:08 GMT
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Mahmood,

On 6/21/16 2:45 PM, Mahmood N wrote:
>> tcp 0 0 0.0.0.0:5666 0.0.0.0:* LISTEN 28122/xinetd Shows the
>> port, 5666, the PID, 28122, and the program name, xinetd
> So, you still don't know what is the IP address (network
> interface)? I mean eth0, eth1 and ...
> 
> Mine is different!
> 
> root@cluster:~# netstat -pat | grep httpd tcp        0      0
> *:ulistproc *:*                         LISTEN      3940/httpd tcp
> 0      0 *:https *:*                         LISTEN
> 3940/httpd

It helps if you don't grep-out the header line that tells you what the
fields mean:

$ sudo netstat -pat | grep '\(^Proto\|httpd\)'
Proto Recv-Q Send-Q Local Address               Foreign Address
      State       PID/Program name
tcp        0      0 *:http                      *:*
      LISTEN      1362/httpd
tcp        0      0 *:81                        *:*
      LISTEN      1362/httpd
tcp        0      0 *:https                     *:*
      LISTEN      1362/httpd

The fourth column tells you the local address, and the "*" means "all
interfaces".

If you use the "-n" switch, you'll get:

tcp        0      0 :::80                       :::*
      LISTEN      1362/httpd
tcp        0      0 :::81                       :::*
      LISTEN      1362/httpd
tcp        0      0 :::443                      :::*
      LISTEN      1362/httpd

So you can see the IP address is "::" (IPv6 "unspecified address")
which means the same thing.

>> The only directive that causes Apache to listen on a network
>> interface is "Listen".
> 
> As I said, that section is commented. So, there should be a default
> ethX and port.

The default interface is always "all interfaces". IF you want to
listen on a specific interface, then do:

Listen 172.20.54.10:80

https://httpd.apache.org/docs/current/mod/mpm_common.html#listen

- -chris
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