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From Rommel Sharma <rsharm...@sapient.com>
Subject RE: [users@httpd] Getting the request URL details using PerlOutputFilterHandler
Date Tue, 26 Jun 2012 07:42:28 GMT
Many thanks Torsten for the valuable inputs. It worked just fine using the approach you provided.
This is great help! Thank you!

I am now checking why perl filtering is not working for pages being served from jboss (routed
to it via the apache web server) when it is working just fine for pages served from Apache's
htdocs (being filtered as expected) and access is fine for jboss pages that are not under
the filter Location. Will be posting that to jboss/mod_perl list. My config is:

<Location ~ "/(staticweb|jbossweb)">
    SetHandler modperl
    PerlOutputFilterHandler MyOutputHandlers::CustomFilterResponse
    allow from all
</Location>

staticweb is under htdocs and jbossweb is an app-context deployed in jboss .

Rommel.


-----Original Message-----
From: Torsten Förtsch [mailto:torsten.foertsch@gmx.net] 
Sent: Monday, June 25, 2012 9:44 PM
To: users@httpd.apache.org
Cc: Rommel Sharma
Subject: Re: [users@httpd] Getting the request URL details using PerlOutputFilterHandler

On 06/25/2012 03:57 PM, Rommel Sharma wrote:
> I am using PerlOutputFilterHandler. I need to customize/filter the output based on where
(for which resource) the request came from.
> 
> How can I find the URL from where the request was made?


sub filter {
  my ($f, $bb)=@_;
  my $r=$f->r;             # this gives you the current request object
                           # see Apache2::RequestRec

  $r->uri;                 # these fields you may be interested in
  $r->unparsed_uri;
  $r->the_request;
  $r->filename;
}

http://perl.apache.org/docs/2.0/api/Apache2/RequestRec.html

Torsten

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