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Subject: RE: htpasswd
Date: Fri, 9 Aug 2002 12:17:54 +0200
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Thread-Topic: htpasswd
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From: "Boyle Owen" <Owen.Boyle@swx.com>
To: <users@httpd.apache.org>
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>From: Philippe Dhont (Sea-ro) [mailto:Philippe.Dhont@searo.be]
>
>I have a little problem;
>When i use
>Htpasswd -c /..../bla/blabla...
>I get the message:
>Htpasswd: -c and -n options conflict
>
>What's the cause of this? As i see it there is no connection=20
>between -c and -n

You see wrong. "-c" means create a file and put the user/pass pairs in =
it. "-n" means send the output to STDOUT. How can the program do both? =
They are mutually exclusive...

The normal procedure is:

- Make a file to begin with:

htpasswd -c mypasswords.pwd joe
	<type in password for joe>

this creates the file mypasswords.pwd with one user/pass pair (i.e. joe) =
inside.

- Later on, add more users:

htpasswd mypasswords.pwd jim
	<type in password for jim>

Note that there is now no "-c" switch since you no longer need to create =
the file since it now exists. The user/pass for jim will be appended to =
the file which now contains a user/pass pair for joe and jim.

If you use the "-n" option, you get the user/pass pair on STDOUT (this =
lets you use htpasswd as a system call in a pipeline or shell-script or =
anything else), e.g.

htpasswd -n joe
	<type in password for joe>
joe:kjLNLO09.5W7

or all on the commandline (add the "-b" switch).

htpasswd -nb joe abcwxyz
joe:kjLNLO09.5W7


Rgds,

Owen Boyle

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