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From "Ladda, Anand" <lan...@microstrategy.com>
Subject RE: Filtering on TIMESTAMP data type
Date Tue, 05 Jun 2012 03:21:21 GMT
Can anyone helpout with the TIMESTAMP literals piece. So far, I've gotten

Select day_timestamp from lu_day where day_timestamp > to_utc_timestamp('2012-06-04 00:00:00',
'GMT') to work ok and give me back timestamps greater than the one in the literal. Is this
the best function to get this to work or is there something else I should be using

From: Ladda, Anand
Sent: Monday, May 28, 2012 11:00 AM
To: user@hive.apache.org
Subject: RE: FW: Filtering on TIMESTAMP data type

Debarshi
Didn't quite follow your first comment. I get the write-your-own UDF part but was wondering
how others have been transitioning from STRING dates to TIMESTAMP dates and getting filtering,
partition pruning, etc to work with constants
-Anand

From: Debarshi Basak [mailto:debarshi.basak@tcs.com]
Sent: Saturday, May 26, 2012 11:54 AM
To: user@hive.apache.org<mailto:user@hive.apache.org>
Subject: Re: FW: Filtering on TIMESTAMP data type

I guess it exist gotta check.
btw...You can always go and write a udf


Debarshi Basak
Tata Consultancy Services
Mailto: debarshi.basak@tcs.com<mailto:debarshi.basak@tcs.com>
Website: http://www.tcs.com
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-----"Ladda, Anand" wrote: -----
To: "user@hive.apache.org<mailto:user@hive.apache.org>" <user@hive.apache.org<mailto:user@hive.apache.org>>,
"dev@hive.apache.org<mailto:dev@hive.apache.org>" <dev@hive.apache.org<mailto:dev@hive.apache.org>>
From: "Ladda, Anand" <lanand@microstrategy.com<mailto:lanand@microstrategy.com>>
Date: 05/26/2012 06:58PM
Subject: FW: Filtering on TIMESTAMP data type
How do I set-up a filter constant for TIMESTAMP datatype. In Hive 0.7 since timestamps were
represented as strings a query like this would return data

select * from LU_day where day_date ='2010-01-01 00:00:00';

But now with day_date as a TIMESTAMP column it doesn't. Is there some type of a TO_TIMESTAMP
function in hive to convert the string constant into a TIMESTAMP one

As a workaround I can do

select * from LU_DAY where TO_DATE(day_date) = '2010-01-01' but that would be a problem for
partitioning pruning, etc



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